我刚刚在几分钟之前发布了另一个问题并解决了问题,现在又有了另一个问题我不知道这个问题出在哪里。
mysql> describe customers;
+-----------+--------------+------+-----+---------+----------------+
| Field | Type | Null | Key | Default | Extra |
+-----------+--------------+------+-----+---------+----------------+
| id | int(10) | NO | PRI | NULL | auto_increment |
| name | varchar(255) | NO | | NULL | |
| email | varchar(255) | NO | | NULL | |
| states_id | tinyint(3) | NO | MUL | NULL | |
+-----------+--------------+------+-----+---------+----------------+
4 rows in set (0.01 sec)
mysql> insert into customers (name, email, states_id) values('Thomas', 't@email.com', 2);
ERROR 1452 (23000): Cannot add or update a child row: a foreign key constraint fails (`crm`.`customers`, CONSTRAINT `customers_ibfk_1` FOREIGN KEY (`states_id`) REFERENCES `states` (`id`) ON UPDATE CASCADE)
mysql> insert into customers (name, email, states_id) values('Thomas', 't@email.com', 2);
ERROR 1452 (23000): Cannot add or update a child row: a foreign key constraint fails (`crm`.`customers`, CONSTRAINT `customers_ibfk_1` FOREIGN KEY (`states_id`) REFERENCES `states` (`id`) ON UPDATE CASCADE)
mysql> describe states
-> ;
+-------+--------------+------+-----+---------+----------------+
| Field | Type | Null | Key | Default | Extra |
+-------+--------------+------+-----+---------+----------------+
| id | tinyint(3) | NO | PRI | NULL | auto_increment |
| name | varchar(255) | YES | | NULL | |
+-------+--------------+------+-----+---------+----------------+
2 rows in set (0.01 sec)
答案 0 :(得分:0)
的结果是什么?
SELECT * FROM states;
我打赌你没有在该表中有ID 2的条目。在您可以在另一个表中插入相关条目之前,引用的ID必须存在于该表中。