Question

我有以下代码，可以自动从数据库中回显学生信息。但是，当用户搜索特定学生时，我需要将相关学生的相同表格重新填充到搜索请求中。

非常感谢所有帮助！

if(!isset ($_POST['search'])){
$pupils = mysql_query("SELECT * FROM pupil") or die("Cant find Pupils");
$count = mysql_num_rows($pupils);    
if ($count == 0 ) {
    $totalpupil = "There are currently no Pupils in the system.";     
} else{
    while($row = mysql_fetch_array($pupils)){
        ?>                                        
                <tr>
                    <td><?php echo '<a href="profile.php?    id='.$row['pupil_id'].'">'.$row['pupil_id'].'</a>'; ?></td>
                    <td><?php echo $row['pupil_name']?></td>
                    <td><?php echo $row['class_id']?></td>
                    <td><a href="pupiledit.php?id='.$id.'">Edit</a> | <a     href="pupildelete.php?id='.$id.'">Delete</a></td>
                </tr>
                <?php
    }       
}
}

Answer 1

这样的东西？

if(!isset ($_POST['search'])){
 $pupils = mysql_query("SELECT * FROM pupil") or die("Cant find Pupils");
}
elseif(isset($_POST['search'])){

 $search_param = "%".$_POST['search']."%";
 $pupils = mysql_query("SELECT * FROM pupil WHERE LOWER(pupil_name) LIKE LOWER($search_param)") or die("Cant find Pupils");
}

$count = mysql_num_rows($pupils);

if($count == 0){
 $totalpupil = "There are currently no Pupils in the system."; 
}
else{
     while($row = mysql_fetch_array($pupils)){
    ?>                                        
            <tr>
                <td><?php echo '<a href="profile.php?    id='.$row['pupil_id'].'">'.$row['pupil_id'].'</a>'; ?></td>
                <td><?php echo $row['pupil_name']?></td>
                <td><?php echo $row['class_id']?></td>
                <td><a href="pupiledit.php?id='.$id.'">Edit</a> | <a     href="pupildelete.php?id='.$id.'">Delete</a></td>
            </tr>
            <?php
}

我假设您正在pupil_name栏中搜索。

使用与搜索匹配的结果重新填充结果表

1 个答案: