在引用数据行中的项目时遇到问题。
当我执行下面的代码时,我的目的是将数据网格视图传输到数据表,与数据进行比较并执行一组特定的事件,但是当我运行
时“ 每个PaymentRow作为DataRow在dtPayments.Rows ”
我发现行中的所有项目都是“DBNull”。
代码在以下行中断
“如果PaymentRow.Item(”Amount“)= PaymentRow.Item(”OutstandingBalance“)则”
由于它无法比较两个DBNull对象而导致的错误
我坚持这个,因为我已经无数次地审查了我的代码,但仍然无法深究它。
提前感谢帮助人员
Private Sub btnSave_Click(sender As System.Object, e As System.EventArgs) Handles btnSave.Click
Dim dtPayments As New DataTable
For Each dgColumn As DataGridViewColumn In dgvInvoices.Columns
Dim dc As New DataColumn
dc.ColumnName = dgColumn.Name
dc.DataType = dgColumn.ValueType
dtPayments.Columns.Add(dc)
Next
For Each dgRow As DataGridViewRow In dgvInvoices.Rows
Dim drow As DataRow = dtPayments.NewRow
For Each dCell As DataGridViewCell In dgRow.Cells
If dCell.OwningColumn.Name = "Amount" Then
If IsDBNull(dCell.Value) Then
drow.Item(dCell.OwningColumn.Name) = 0.0
Else
drow.Item(dCell.OwningColumn.Name) = dCell.Value
End If
Else
drow.Item(dCell.OwningColumn.Name) = dCell.Value
End If
Next
dtPayments.Rows.Add(dgRow)
Next
For Each PaymentRow As DataRow In dtPayments.Rows
Dim strInvoiceRef As String = PaymentRow.Item("InvoiceRef").ToString
If PaymentRow.Item("Amount") = PaymentRow.Item("OutstandingBalance") Then
CreateDebit(PaymentRow.Item("Amount"), strInvoiceRef)
CropTrackMod.PaidInvoiceHeader(strInvoiceRef, True)
Dim dtTicketsOnInvoice As DataTable = CropTrackMod.GetDistinctTicketsOnInvoice(strInvoiceRef)
For Each DistinctRow As DataRow In dtTicketsOnInvoice.Rows
'set this list to paid
CropTrackMod.PaidTicket(DistinctRow.Item("TicketRef").ToString(), True)
Next
ElseIf PaymentRow.Item("AmountPaid") < PaymentRow.Item("OutstandingBalance") Then
CreateDebit(PaymentRow.Item("Amount"), strInvoiceRef)
End If
Next
End Sub
答案 0 :(得分:0)
除了检查&#34;金额&#34;,还要检查&#34; OutstandingBalance&#34;循环遍历行时是DBNull。这样它也将被设置为0.0,因此您之后的比较是有效的:
For Each dgRow As DataGridViewRow In dgvInvoices.Rows
Dim drow As DataRow = dtPayments.NewRow
For Each dCell As DataGridViewCell In dgRow.Cells
If dCell.OwningColumn.Name = "Amount" Or dCell.OwningColumn.Name = "OutstandingBalance" Then
etc.