Question

我想计算两个日期之间的差异，一个是从dateTimePicker1中选择的，另一个是2014年2月20日，并将其存储在一个字符串中以添加到我的数组中，并能够以另一种形式显示

这是我的代码：

    TimeSpan getDateDifference(DateTime date1, DateTime date2)
    {
        TimeSpan ts = date1 - date2;
        int differenceInDays = ts.Days;
        string differenceAsString = differenceInDays.ToString();
        return ts;

    }


    public class Patient
    {
        public string patientidString;
        public string firstNameString;
        public string lastNameString;
        public string dateString;
        public string differenceAsString;


        public Patient()
        {
            patientidString = "";
            firstNameString = "";
            lastNameString = "";
            dateString = "";
        }

    }


    //Array
    Patient[] patientInfo = new Patient[10];




    private void button1_Click(object sender, EventArgs e)
    {
        TimeSpan difference = getDateDifference(new DateTime(2014, 2, 20), dateTimePicker1.Value);
        if (textBox1.Text.Length == 0 || textBox2.Text.Length == 0 || textBox3.Text.Length == 0)
        {
            MessageBox.Show(" Patient id, first name and last name cannot be empty");
        }

        else
        try
        {
            foreach (Patient patientinfoIndex in patientInfo)

            patientInfo[itemCountInteger].patientidString = textBox1.Text;
            patientInfo[itemCountInteger].firstNameString = textBox2.Text;
            patientInfo[itemCountInteger].lastNameString = textBox3.Text;
            patientInfo[itemCountInteger].dateString = dateTimePicker1.Text;

            string names = patientInfo[itemCountInteger].patientidString + "  " + patientInfo[itemCountInteger].firstNameString + " " + patientInfo[itemCountInteger].lastNameString;
            listBox1.Items.Add(names);
            itemCountInteger++;
            listBox1.SelectedItem = names;
        }
        catch
        {
            MessageBox.Show("Contacts are limited to 20. Please delete some contacts prior to adding more.");
        }


    }


    //Search Button search a patients name and display his surname in the label if patient is found  display his surname
    private void button2_Click(object sender, EventArgs e)
    {

        int intTest = 0;

        for (int x = 0; x < patientInfo.Length; x++)
        {
            if (textBox4.Text == patientInfo[x].patientidString)
            {
                label6.Text = (patientInfo[x].firstNameString + "  " + patientInfo[x].lastNameString);
                PatientForm patientform = new PatientForm();
                patientform.Show();
                patientform.label6.Text = (patientInfo[x].patientidString);
                patientform.label7.Text = (patientInfo[x].firstNameString);
                patientform.label8.Text =(patientInfo[x].lastNameString);
                patientform.dateTimePicker1.Text = (patientInfo[x].dateString);

patientform.label9.Text = (patientInfo[x].differenceAsString);

                intTest = 1;
                break;
            }

        }

        if (intTest == 0)
        {
            label6.Text = ("not found");
        }
    }

Answer 1

DateTime febDate = new DateTime(2014, 2, 20);
DateTime pickerDate = myDateTimePicker.Value;

TimeSpan tspan = febDate - pickerDate;

int differenceInDays = tspan.Days;

string differenceAsString = differenceInDays.ToString();

如果differenceInDays < 0则将其乘以-1。

注意：在这种情况下，也可以很容易地得到小时，分钟或秒的差异。

以上是自己方法中上述代码的示例：

TimeSpan getDateDifference(DateTime date1, DateTime date2)
{
    TimeSpan ts = date1 - date2;

    return ts;
}

当你想要触发这个方法时：

TimeSpan difference = getDateDifference(new DateTime(2014, 2, 20), dateTimePicker.Value);

//Now you can do what you want with the TimeSpan.

int differenceInDays = difference.Days;
int differenceInHours = difference.Hours; 

Console.WriteLine(differenceInDays.ToString());

Answer 2

DateTime a = new DateTime.Parse(string);
Console.WriteLine(datePicker.Value.Subtract(a).TotalMinutes);

Answer 3

你可以减去任何两个日期，它会起作用。

DateTime date1 = new DateTime(2014,02,20);
DateTime date2 = dateTimePicker1.Value as DateTime;

TimeSpan difference = date1 - date2;  //dunno what difference you need so you can swap these

计算datetimepicker中2个日期之间的差异

3 个答案: