Question

我有一个包含有关某人信息的数据库。让我们说我想搜索一个国家的人。所以我输入美国并得到10个数据。在那之后，我想进一步缩小到男性。

如何执行首先搜索国家/地区的SQL，然后搜索性别。

$sql="SELECT * FROM people 
  WHERE country like $search1%
  ORDER BY ASC ";

和

$sql="SELECT * FROM people 
  WHERE country like $search1%
  AND Gender = $search2
  ORDER BY ASC ";

如何将它们组合成一个$ sql语句？

Answer 1

尝试将所有案例与此代码结合使用：

$sql = "SELECT *
FROM people
WHERE (country LIKE %$search1% AND $search2='')
OR ($search1='' AND gender=$search2)
OR (country LIKE %$search1% AND gender=$search2)";

添加您自己的ORDER BY子句。

Answer 2

更新

SELECT * 
FROM people 
WHERE 
((country = ('USA') AND gender = 'male') 
OR 
(country LIKE ('USA') OR gender LIKE 'male'))
ORDER BY ASC

第一行((country = ('USA') AND gender = 'male')

两者兼而有之第二行(country LIKE ('USA') OR gender LIKE 'male'))

将'%'放入您不需要的地方。

例如(country LIKE ('USA') OR gender LIKE '%'))

Answer 3

子查询：

SELECT * FROM（SELECT * FROM people WHERE country like $ search1％） as people1 WHERE Gender = $ search2 ORDER BY ASC

Answer 4

你可以结合这个。首先检查过滤器是否有值。

检查使用if条件并连接一个字符串然后执行它，就像一个。

$sql="SELECT * FROM people WHERE 1 ";
if($search1% != NULL){
   $sql.="AND country like $search1% ";
}
elseif($search2 != NULL){
   $sql.="AND Gender = $search2 ";
}
$sql.="ORDER BY ASC ";

Answer 5

有两种方式

在MySql中创建视图对于此类复杂查询

在php中编写一个函数来构建上面的查询

 <?php
   function searchQuery($key,$gender,$order){
     $sql = "SELECT * FROM people WHERE country like %$key% AND Gender = $gender ORDER BY $order"
    $query= mysql_query($sql);
    while($data= mysql_fetch_array($query))  {
       //Do your stuff here and collect in one variable say $searchData
    }
     return $searchData
   }

希望这会对你有所帮助

多个搜索过滤MySQL数据库

5 个答案: