Question

我需要让用户输入一个高度值，如果它高于23或小于0，它应该再次询问。然后应该在马里奥兄弟游戏结束时打印一个类似楼梯的金字塔（右侧有2个标签，参见示例）。问题是代码运行并且不打印任何＃，代码结束。这是一个在线课程，所以请不要只发布代码，如果你要发布完整的代码请解释。

金字塔示例：https://www.dropbox.com/s/4fyg2ls0eml7asi/Screenshot%20from%202014-03-20%2002%3A15%3A08.png

我遵循的流程图：http://i.imgur.com/otuDOtK.png

#include <stdio.h>
//#include "cs50.h"

int main(void){
    //int h = 0;
    printf("Enter height between 0 and 23: ");
    int h = scanf("%d", &h);
    while (h < 0 || h > 23){
        printf("Retry: ");
        h = scanf("%d", &h);
    }
    int l = 1;
    if (h == 0){
        //printf("ln21\n"); //Debug
        return;
    }
    int s = h - 1;
    int b = l + 1;
    if (s == 0){
        if (b == 0){
            printf("\n");
    h = h - 1;
    l = l + 1;
    if (h == 0){
        return;
    }
        }
    }
    else{
    printf("#");
    b = b - 1;
    }
}

Answer 1

#include <stdio.h>

int main(){
    int height = 8;//Number of repetitions of basic.
    int max_width = height + 1;//Number of block(#) in the largest display
    int i, j, w;
    for(i = 0; i < height; ++i){
        printf("%*s", max_width -(i+2), "");//Print a space in front of the block
        for(w = 0; w < i+2; ++w){
            printf("#");//display a block of each floor
        }
        printf("\n");
    }
    printf("\n");
    return 0;
}

#include <stdio.h>
#include <string.h>

int main(){
    int height = 8;
    int max_width = height + 1;
    char wall[max_width + 1];
    int i;
    memset(wall, '#', sizeof(wall)-1);// make a block of maximum.
    wall[sizeof(wall)-1] = '\0';
    for(i = 0; i < height; ++i){
        printf("%*.*s\n", max_width, i+2, wall);//View of block size and the required blank
    }
    return 0;
}

C - 当用户输入高度时，需要用＃打印金字塔

1 个答案: