Question

我想允许我的网站管理员过滤管理网站上特定国家/地区的用户。所以自然要做的就是这样：

#admin.py
class UserAdmin(django.contrib.auth.admin.UserAdmin):
    list_filter=('userprofile__country__name',)

#models.py
class UserProfile(models.Model)
    ...
    country=models.ForeignKey('Country')

class Country(models.Model)
    ...
    name=models.CharField(max_length=32)

但是，由于在django中处理用户及其UserProfile的方式，这会导致以下错误：

'UserAdmin.list_filter[0]' refers to field 'userprofile__country__name' that is missing from model 'User'

如何解决这个限制？

Answer 1

您要找的是自定义管理员FilterSpecs 。坏消息是，对这些人的支持可能不会很快发布（你可以跟踪讨论here）。

然而，以肮脏的黑客为代价，您可以解决限制问题。在深入研究代码之前，有关如何构建FilterSpecs的一些要点：

在构建要在页面上显示的FilterSpec列表时，Django会使用您在list_filter
这些字段必须是模型上的真实字段，而不是反向关系，也不是自定义属性。
Django维护一个FilterSpec类列表，每个类与测试函数相关联。
对于list_filter中的每个字段，Django将使用 test 函数为该字段返回 True 的第一个FilterSpec类。< / LI>

好的，现在考虑到这一点，请看下面的代码。它改编自a django snippet。代码的组织由您自行决定，请记住，这应该由admin应用导入。

from myapp.models import UserProfile, Country
from django.contrib.auth.models import User
from django.contrib.auth.admin import UserAdmin

from django.contrib.admin.filterspecs import FilterSpec, ChoicesFilterSpec
from django.utils.encoding import smart_unicode
from django.utils.translation import ugettext_lazy as _

class ProfileCountryFilterSpec(ChoicesFilterSpec):
    def __init__(self, f, request, params, model, model_admin):
        ChoicesFilterSpec.__init__(self, f, request, params, model, model_admin)

        # The lookup string that will be added to the queryset
        # by this filter
        self.lookup_kwarg = 'userprofile__country__name'
        # get the current filter value from GET (we will use it to know
        # which filter item is selected)
        self.lookup_val = request.GET.get(self.lookup_kwarg)

        # Prepare the list of unique, country name, ordered alphabetically
        country_qs = Country.objects.distinct().order_by('name')
        self.lookup_choices = country_qs.values_list('name', flat=True)

    def choices(self, cl):
        # Generator that returns all the possible item in the filter
        # including an 'All' item.
        yield { 'selected': self.lookup_val is None,
                'query_string': cl.get_query_string({}, [self.lookup_kwarg]),
                'display': _('All') }
        for val in self.lookup_choices:
            yield { 'selected' : smart_unicode(val) == self.lookup_val,
                    'query_string': cl.get_query_string({self.lookup_kwarg: val}),
                    'display': val }

    def title(self):
        # return the title displayed above your filter
        return _('user\'s country')

# Here, we insert the new FilterSpec at the first position, to be sure
# it gets picked up before any other
FilterSpec.filter_specs.insert(0,
  # If the field has a `profilecountry_filter` attribute set to True
  # the this FilterSpec will be used
  (lambda f: getattr(f, 'profilecountry_filter', False), ProfileCountryFilterSpec)
)


# Now, how to use this filter in UserAdmin,
# We have to use one of the field of User model and
# add a profilecountry_filter attribute to it.
# This field will then activate the country filter if we
# place it in `list_filter`, but we won't be able to use
# it in its own filter anymore.

User._meta.get_field('email').profilecountry_filter = True

class MyUserAdmin(UserAdmin):
  list_filter = ('email',) + UserAdmin.list_filter

# register the new UserAdmin
from django.contrib.admin import site
site.unregister(User)
site.register(User, MyUserAdmin)

它显然不是灵丹妙药，但它会完成工作，等待更好的解决方案出现。（例如，将继承ChangeList并覆盖get_filters）。

Answer 2

Django 1.3修复了它。您现在可以在list_filter

中跨越关系

https://docs.djangoproject.com/en/1.3/ref/contrib/admin/#django.contrib.admin.ModelAdmin.list_filter

Django-Admin：UserProfile的list_filter属性

2 个答案: