我目前正在通过mysql在blueimp / jquery-file-upload脚本中插入标题和描述。我使用this教程将我带到那里,但是,我需要添加另一个变量。该变量是当前登录用户ID $_SESSION["userid"]
的会话,我想将其插入到我添加的名为uid
的列中。通常很容易将另一列插入到插入中,但是这个脚本非常敏感,任何时候我都搞乱它,即使是最轻微的一点,我得到“SyntaxError: Unexpected token <
”。任何帮助将不胜感激。
$options = array(
'delete_type' => 'POST',
'db_host' => 'localhost',
'db_user' => 'fpform_fanuser',
'db_pass' => '*****',
'db_name' => 'fpform_fandata',
'db_table' => 'files'
);
error_reporting(E_ALL | E_STRICT);
require('UploadHandler.php');
class CustomUploadHandler extends UploadHandler {
protected function initialize() {
$this->db = new mysqli(
$this->options['db_host'],
$this->options['db_user'],
$this->options['db_pass'],
$this->options['db_name']
);
parent::initialize();
$this->db->close();
}
protected function handle_form_data($file, $index) {
$file->title = @$_REQUEST['title'][$index];
$file->description = @$_REQUEST['description'][$index];
}
protected function handle_file_upload($uploaded_file, $name, $size, $type, $error,
$index = null, $content_range = null) {
$file = parent::handle_file_upload(
$uploaded_file, $name, $size, $type, $error, $index, $content_range
);
if (empty($file->error)) {
$sql = 'INSERT INTO `'.$this->options['db_table']
.'` (`name`, `size`, `type`, `title`, `description`)'
.' VALUES (?, ?, ?, ?, ?)';
$query = $this->db->prepare($sql);
$query->bind_param(
'sisss',
$file->name,
$file->size,
$file->type,
$file->title,
$file->description,
);
$query->execute();
$file->id = $this->db->insert_id;
}
return $file;
}
protected function set_additional_file_properties($file) {
parent::set_additional_file_properties($file);
if ($_SERVER['REQUEST_METHOD'] === 'GET') {
$sql = 'SELECT `id`, `type`, `title`, `description` FROM `'
.$this->options['db_table'].'` WHERE `name`=?';
$query = $this->db->prepare($sql);
$query->bind_param('s', $file->name);
$query->execute();
$query->bind_result(
$id,
$type,
$title,
$description
);
while ($query->fetch()) {
$file->id = $id;
$file->type = $type;
$file->title = $title;
$file->description = $description;
}
}
}
public function delete($print_response = true) {
$response = parent::delete(false);
foreach ($response as $name => $deleted) {
if ($deleted) {
$sql = 'DELETE FROM `'
.$this->options['db_table'].'` WHERE `name`=?';
$query = $this->db->prepare($sql);
$query->bind_param('s', $name);
$query->execute();
}
}
return $this->generate_response($response, $print_response);
}
}
$upload_handler = new CustomUploadHandler($options);
答案 0 :(得分:0)
假设您要更改INSERT查询(您发布的代码中只有一个INSERT查询),这就是您需要更改的内容:
if (empty($file->error)) {
$sql = 'INSERT INTO `'.$this->options['db_table']
.'` (`name`, `size`, `type`, `title`, `description`, `uid`)'
.' VALUES (?, ?, ?, ?, ?, ?)';
$query = $this->db->prepare($sql);
$query->bind_param(
'sisss',
$file->name,
$file->size,
$file->type,
$file->title,
$file->description,
$_SESSION['userid']
);
$query->execute();
$file->id = $this->db->insert_id;
}
答案 1 :(得分:0)
protected function handle_file_upload($uploaded_file, $name, $size, $type, $error,
$index = null, $content_range = null, $uid) {
$file = parent::handle_file_upload(
$uploaded_file, $name, $size, $type, $error, $index, $content_range, $uid
);
$uid=$_SESSION['userid'];
if (empty($file->error)) {
$sql = 'INSERT INTO `'.$this->options['db_table']
.'` (`name`, `size`, `type`, `title`, `description`,`uid`)'
.' VALUES (?, ?, ?, ?, ?,?)';
$query = $this->db->prepare($sql);
$query->bind_param(
'sisssi',
$file->name,
$file->size,
$file->type,
$file->title,
$file->description,
$file->uid
);
$query->execute();
$file->id = $this->db->insert_id;
}
return $file;
}`
答案 2 :(得分:0)
我认为你必须在bind_param的第一个参数中添加另一个条目:
$query->bind_param(
**'sisss',**
$file->name,
$file->size,
$file->type,
$file->title,
$file->description,
$_SESSION['userid']
应该是
$query->bind_param(
**'sissss',**
$file->name,
$file->size,
$file->type,
$file->title,
$file->description,
$_SESSION['userid']
当然,减去星号或任何正确的数据类型(请参阅http://us.php.net/manual/en/mysqli-stmt.bind-param.php处的参数类型部分)。
有一个奇怪的是,我尝试将一个文字字符串作为最后一个参数传递,并且它抛出了这个错误:
&#34; PHP致命错误:无法在第66和34行的/var/www/html/jqfileuploadertest/server/php/index.php中通过引用传递参数7;
但是当我改变了#mys;&#39;到$ file-&gt;名称它工作正常。这将需要一些摔跤,因为我想给这些时间戳...我有一种感觉只是添加&#34; NOW()&#34;没有去上班......
更新:我想为每个文件添加两个字段,上传者的ID(我认为OP正在寻找的内容)以及时间戳。我在表格中添加了隐藏的输入:
<input name="contributor[]" type="hidden" value="myuserid" />
<input name="uploadedOn[]" type="hidden" value="2014-03-28 10:00:00" />
如果您的表单是php脚本,则可以动态生成两者。
然后将其添加到index.php第44行:
$file->contributor = @$_REQUEST['contributor'][$index];
$file->uploadedOn = @$_REQUEST['uploadedOn'][$index];
并修改了index.php的这一部分,其中准备了sql语句:
if (empty($file->error)) {
$sql = 'INSERT INTO `'.$this->options['db_table']
.'` (`name`, `size`, `type`, `title`, `description`,`contributor`, `dateUploaded`)'
.' VALUES (?, ?, ?, ?, ?, ?, ?)';
$query = $this->db->prepare($sql);
$query->bind_param(
'sisssss',
$file->name,
$file->size,
$file->type,
$file->title,
$file->description,
$file->contributor,
$file->uploadedOn
);
它有效。
答案 3 :(得分:0)
当您正确上传文件时,您在javascript控制台中收到的错误是什么?在我看来,正在加载的文件之一是404找不到,并且它试图将收到的404页面解析为脚本文件,而实际上它是一个以&lt; ...开头的html文件。在网络下检查并查看发生时正在加载的所有资源。可能没有返回正确的404标头,这就是为什么它会尝试解析它。