Question

public static void main(String[] args) {

    int maxNum, sum, counter; // input value
    Scanner input = new Scanner(System.in); 

    System.out.print("How many odd numbers should I add up?: ");
    maxNum = input.nextInt();   

    sum = 0;

    for (counter = 1; counter < maxNum; counter++)
    {            
       sum = counter + maxNum;                        
    }

    System.out.println("\n" + "The sum of the odd numbers between 1 and " + maxNum + " is: " + sum);                 
}

根据具体的代码，它应该只通过奇数来解决加法问题。

现在我尝试了一个数字，5，根据我的输出：

How many odd numbers should I add up?: 5

The sum of the odd numbers between 1 and 5 is: 9

有效。但是当我尝试用另一个数字10时，出了点问题：

How many odd numbers should I add up?: 10

The sum of the odd numbers between 1 and 10 is: 19

我知道我的数学问题，但是从1到10的奇数不能加到19，它总计达到25。

代码有问题。任何人都可以找出问题所在吗？

Answer 1

   for (counter = 1; counter < maxNum; counter+=2)
   {
      sum += counter;                                 
   }

您添加的号码错误。

Answer 2

您的for循环正在添加错误的号码，需要跳过其他所有号码。

for (counter = 1; counter <= maxNum; counter+=2)
{
   sum += counter;                                 
}

输出（如果我们添加调试）：

counter = 1,sum = 1
counter = 3,sum = 4
counter = 5,sum = 9
counter = 7,sum = 16
counter = 9,sum = 25

另一种方法是使用while循环：

counter = 1;
while(counter < maxNum) 
{
   if (counter % 2 != 0) 
   {
      sum += counter;          
   }
   counter++;
}

输出（如果我们添加调试）：

counter = 1,sum = 1
counter = 3,sum = 4
counter = 5,sum = 9
counter = 7,sum = 16
counter = 9,sum = 25

Answer 3

将此代码用于循环内部。

if(counter%2==1){
    sum=sum+counter;

Answer 4

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;

namespace Part_C_6
{
    class Program
    {
        static void Main(string[] args)
        {
            int n;
            Console.WriteLine("Enter N");
            n = int.Parse(Console.ReadLine());

            Console.WriteLine(odd(n));

        }

        public static int odd(int x)
        {

            int j,ans=0;
            for (j = 1; j < x; j+=2)
            {
                ans = ans + j;
            }
            return ans;

        }

    }
}

Answer 5

public static void main(String[] args) {

int maxNum, sum, counter; // input value
Scanner input = new Scanner(System.in); 

System.out.print("How many odd numbers should I add up?: ");
maxNum = input.nextInt();   

sum = 0;

for (counter = 1; counter <= maxNum; counter+=2)

{

sum += counter;   

/* 
Working of loop
counter = 1,sum = 1
counter = 3,sum = 4
counter = 5,sum = 9
counter = 7,sum = 16
counter = 9,sum = 25                         
*/

}
System.out.println("\n" + "The sum of the odd numbers between 1 and " + maxNum + " is: " + sum);                 
}

Answer 6

在你的for循环中，你将计数器增加一个

如果您只需要奇数，则应更改

for (counter = 1; counter < maxNum; counter++)

到

for (counter = 1; counter <= maxNum; counter+=2)

和

sum = counter + maxNum;

到

sum += counter;

在循环中求和奇数

6 个答案: