Question

是的，之前已经问过这个问题，但问题是运营商是会员功能，而且这不是问题。这些是我的文件：

minmax.h

#ifndef MINMAX_H
#define MINMAX_H

class MinMax
{
private:
    int m_nMin;
    int m_nMax;

public:
    MinMax(int nMin, int nMax);

    int GetMin() { return m_nMin; }
    int GetMax() { return m_nMax; }

    friend MinMax operator+(const MinMax &cM1, const MinMax &cM2);
    friend MinMax operator+(const MinMax &cM, int nValue);
    friend MinMax operator+(int nValue, const MinMax &cM);
};

#endif // MINMAX_H

minmax.cpp

#include "minmax.h"

MinMax::MinMax(int nMin, int nMax)
{
    m_nMin = nMin;
    m_nMax = nMax;
}

MinMax MinMax::operator+(const MinMax &cM1, const MinMax &cM2)
{
    //compare member variables to find minimum and maximum values between all 4
    int nMin = cM1.m_nMin < cM2.m_nMin ? cM1.m_nMin : cM2.m_nMin;
    int nMax = cM1.m_nMax > cM2.m_nMax ? cM1.m_nMax : cM2.m_nMax;

    //return a new MinMax object with above values
    return MinMax(nMin, nMax);
}

MinMax MinMax::operator+(const MinMax &cM, int nValue)
{
    //compare member variables with integer value
    //to see if integer value is less or greater than any of them
    int nMin = cM.m_nMin < nValue ? cM.m_nMin : nValue;
    int nMax = cM.m_nMax > nValue ? cM.m_nMax : nValue;

    return MinMax(nMin, nMax);
}

MinMax MinMax::operator+(int nValue, const MinMax %cM)
{
    //switch argument places and pass them to previous operator version
    //this avoids duplicate code by reusing function
    return (cM + nValue);
}

的main.cpp

#include <iostream>
#include "minmax.h"

using namespace std;

int main()
{
    MinMax cM1(10, 15);
    MinMax cM2(8, 11);
    MinMax cM3(3, 12);

    //sum all MinMax objects to find min and max values between all of them
    MinMax cMFinal = cM1 + 5 + 8 + cM2 + cM3 + 16;
    cout << cMFinal.GetMin() << ", " << cMFinal.GetMax() << endl;

    return 0;
}

消息显示为error: 'MinMax MinMax::operator+(const MinMax&, const MinMax&)' must take either zero or one argument

Answer 1

将我的评论转变为答案：

您通过将MinMax::放在其前面来将您的功能定义为成员函数，因此成员函数。

MinMax MinMax::operator+(const MinMax &cM, int nValue)
{  // should be operator+ without the MinMax:: at the front.

    //compare member variables with integer value
    //to see if integer value is less or greater than any of them
    int nMin = cM.m_nMin < nValue ? cM.m_nMin : nValue;
    int nMax = cM.m_nMax > nValue ? cM.m_nMax : nValue;

    return MinMax(nMin, nMax);
}

你可以看到它正常工作here

Answer 2

正如您所说，他们不是会员职能。

因此，在他们的定义中，MinMax::前缀不正确，不应该在那里。

重载运算符必须采用零个或一个参数

2 个答案: