Question

我编写了一个程序，其中调用一个函数，该函数返回一个二维数组指针，并将一个二维数组作为参数。但不知怎的，在运行函数时没有调用。我无法弄明白。任何建议

#include <stdio.h>
#include <stdlib.h>
signed char** complement(signed char no_of_variables[20][20]);
int main(void)
{

  FILE *ptr_file;
  FILE *ptr_file1;
  FILE *ptr_file2;
  signed char **no_of_variables_or3;
  //signed char **no_of_variables_or2;

  signed char i, j, k, w;
  signed char no_of_variables[20][20], no_of_variables2[23][1000];
  //char no_of_sops[1];
  //char a = no_of_sops[0];

  //char value[a][10];
  ptr_file = fopen("part1.txt", "r+");
  if (!ptr_file)
    return 1;
  for (i = 0; i < 2; i++)
  {
    fgets(no_of_variables[i], 20, ptr_file);
  }
  for (i = 0; i < no_of_variables[1][0]; i++)
  {
    fgets(no_of_variables[i + 2], 20, ptr_file);
  }

  fclose(ptr_file);

  signed char var = 2 + (no_of_variables[1][0] - 48);
  for (i = 0; i < (var); i++)
  {
    for (j = 0; j < 20; j++)
    {
      no_of_variables[i][j] = no_of_variables[i][j] - 48;
    }
  }

  for (i = 0; i < 23; i++)
  {
    //for( j=0;j<1000;j++){
    //  outputarray[i][j] = " ";
    printf("val%d\n", no_of_variables[i][0]);
  }

  no_of_variables_or3 = complement(no_of_variables[20][20]);

  FILE *optr_file;
  optr_file = fopen("output_part1.txt", "r+");
  if (!optr_file)
    return 1;
  for (i = 0; i < 2; i++)
  {
    fputs(no_of_variables_or3[i], optr_file);
  }
  for (i = 0; i < no_of_variables_or3[1][0]; i++)
  {
    fputs(no_of_variables_or3[i + 2], optr_file);

  }
  fclose(optr_file);
  return EXIT_SUCCESS;
}

Answer 1

更改此行：

no_of_variables_or3 = complement(no_of_variables[20][20]);

是：

no_of_variables_or3 = complement(no_of_variables);

编译器应该通过发出警告来指出这一点。

功能未被调用

1 个答案: