Question

我正在尝试根据先前查询中获得的值进行查询。这样的事情：

$variableid = 100;

$query_prev = "SELECT query FROM queries_table WHERE id = 1";
$result_prev = pg_query($pg,$query_prev);
$row_prev = pg_fetch_array($result_prev);


$final_query = $row_prev['query']; 

$row_prev['query'] value would be "SELECT * FROM other_table WHERE id = $variableid";

$final_query value at this point is: "SELECT * FROM other_table WHERE id = $variableid"

/* but that I want is this value: */ "SELECT * FROM other_table WHERE id = 100"

Answer 1

在进行下一次选择之前使用if语句：

<?php if ($row_prev['query']= 100){

    SELECT .......... etc.
    }else
    SELECT from other

    ?>

/希望这就是你想要的

Answer 2

解决：

$variableid = 100;

$query_prev = "SELECT query FROM queries_table WHERE id = 1";
$result_prev = pg_query($pg,$query_prev);
$row_prev = pg_fetch_array($result_prev);
$query = $row_prev['query']; 

eval("\$final_query = \"$query\";");

PHP：变量到字符串查询

2 个答案: