Question

我有一个主菜单，其中包含许多项目，这些项目又会打开不同的表单。目前我执行以下操作来打开特定表单：

        if (canShowCustomerForm)
            new CustomerForm().ShowDialog(this);
        else
        {
            MessageBox.Show("You don't have enough rights to view this form.");
        }

有没有办法在类中移动此代码，然后传递表单类型和布尔参数，而不是为每个菜单项重复代码？

Answer 1

public static class FormHelper
{
    public static DisplayResult ShowForm<T>(IWin32Window owner, bool canShowForm)
        where T : Form, new()
    {
        if (canShowForm)
        {
            using (T form = new T())
            {
                return form.ShowDialog(owner);
            }
        }
        else
        {
            MessageBox.Show("You don't have enough rights to view this form.");
        }
    }
}

Answer 2

不是一遍又一遍地编写相同的逻辑，而是将其提取到如下函数中：

void ShowFormIfAllowed<TForm>(bool allowed) where TForm : Form, new() {
      if (allowed) {
          using (var form = new TForm()) {
               form.ShowDialog(this);
          }
      }
      else {
            MessageBox.Show("You don't have enough rights to view this form.");
      }
 }

然后在您的菜单处理中，您可以将其称为：

ShowFormIfAllowed<CustomerForm>(canShowCustomerForm);

C＃使用泛型打开表单？

2 个答案: