Question

我正在使用此代码：

preg_match("/^.*\[Ticket ID\: \#(\d*)\].*$/", $subject, $output_array);
$ticketnumber = $output_array[1];

回显字符串中的数字，如：

[Ticket ID: #1234]

$ subject变量中的

并将其放入$ticketnumber变量

我如何检查主题变量中是否存在[Ticket ID: #1234]？

Answer 1

尝试strpos()：

示例：

$mystring = 'abc';
$findme   = 'a';
$pos = strpos($mystring, $findme);

// Note our use of ===.  Simply == would not work as expected
// because the position of 'a' was the 0th (first) character.
if ($pos === false) {
    echo "The string '$findme' was not found in the string '$mystring'";
} else {
    echo "The string '$findme' was found in the string '$mystring'";
    echo " and exists at position $pos";
}

在您的方案中，您需要尝试这样：

 $findme='[Ticket ID: #1234]';
 $pos = strpos($subject, $findme);
if($pos){
 //it  contains
}
else {
//not containing
}

Answer 2

我假设您正在尝试确定提供的主题中是否存在ticketnumber。

您可以尝试这样的事情：

<?php

// input
$subject = "[Ticket ID: #1234]";

// parse
preg_match("/^.*\[Ticket ID\: \#(\d*)\].*$/", $subject, $output_array);
$ticketnumber = isset($output_array[1]) ? intval($output_array[1]) : null;

// validate
if ($ticketnumber)
{
    // A ticket number was found in subject
}
else
{
    // not found
}

?>

PHP检查字符串是否在变量中

2 个答案: