Question

我只想替换代码方便Url.Content而不是使用ViewBag。我怎么能这样做？

<a href="@Url.Content("~/Bike/")">Home</a>
   <ul>
       <li>
           <a href="@Url.Content("~/Bike/Categories/1?name=Mountain Bikes&class=image")">Mountain Bikes</a>
       </li>
       <li>
           <a href="@Url.Content("~/Bike/Categories/2?name=Road Bikes&class=image")">Road Bikes</a>
       </li>
       <li>
           <a href="@Url.Content("~/Bike/Categories/3?name=Touring Bikes&class=image")">Touring Bikes</a>
       </li>

   </ul>

ViewBag：

 ViewBag.Menu = BikesDB.ProductSubcategories
                .Where(m => m.isSelected == true).AsEnumerable()
                .Select(p => new Bike { 
                                        Id = p.ProductSubcategoryID,
                                        Name = p.NameofBike 
                         });

Answer 1

您需要使用以下内容::

<a href="@Url.Content("~/Bike/")">Home</a>
<ul>


    @foreach (var item in @ViewBag.Menu)
    {
       <li>
          <a href="@Url.Content("~/Bike/Categories/"+item.ID+"?name="+item.Name+"&class=image")">@item.Name</a>
       </li>   
    }

</ul>

因为您制作的ViewBag包含多个条目（即可枚举）

ViewBag.Menu = BikesDB.ProductSubcategories
                .Where(m => m.isSelected == true).AsEnumerable()
                .Select(p => new Bike { 
                                        Id = p.ProductSubcategoryID,
                                        Name = p.NameofBike 
                         });

ViewBag动态Url.Content

1 个答案: