Question

我正在尝试创建一个表并为其行赋值，但它无效。任何提示或建议将不胜感激：

<!DOCTYPE html>
<html>

<head>
<style>
table,th,td
{
border:1px solid black;
border-collapse:collapse;
}
th,td
{
padding:5px;
}
</style>
</head>
<?php
    $subject = "ISIT307";
    $location = "3.123";
    $time = "4:30";

<table style="width:300px">
<tr>
  <th>Subject</th>
  <th>location</th> 
  <th>time</th> 
</tr>
<tr>
  <td>$subject</td>
  <td>$location</td> 
  <td>$time</td>
</tr>
</table>
?>
</body>
</html>

Answer 1

尝试以下方法：

<tr>
  <td><?php echo $subject; ?></td>
  <td><?php echo $location; ?></td> 
  <td><?php echo $time; ?></td>
</tr>

只要您想运行php代码，就需要使用<?php和?>。

Answer 2

$ time =＆＃34; 4:30＆＃34 ;;后面有语法错误你不能直接通过php输出html，你可以调用echo或print。

<!DOCTYPE html>
<html>

<head>
<style>
table,th,td
{
border:1px solid black;
border-collapse:collapse;
}
th,td
{
padding:5px;
}
</style>
</head>
<?php
    $subject = "ISIT307";
    $location = "3.123";
    $time = "4:30";
?>

<table style="width:300px">
<tr>
  <th>Subject</th>
  <th>location</th> 
  <th>time</th> 
</tr>
<tr>
  <td><?= $subject ?></td>
  <td><?= $location ?></td> 
  <td><?= $time ?></td>
</tr>
</table>
</body>
</html>

Answer 3

你的php中没有html，你的html中也没有php。

<?php
    $subject = "ISIT307";
    $location = "3.123";
    $time = "4:30";
?>

<table style="width:300px">
<tr>
  <th>Subject</th>
  <th>location</th> 
  <th>time</th> 
</tr>
<tr>
  <td><?=$subject ?></td>
  <td><?=$location ?></td> 
  <td><?=$time ?></td>
</tr>
</table>

如何在PHP代码中嵌入表？

3 个答案: