Question

继承了Wapiti的一次扫描。我注意到我上传了图片（用户可以上传），我在Launching module crlf之前遇到了崩溃。所以，只需使用我的网站的新实例，我运行了这个并得到了下面的结果。

我的问题是 1.我如何解决崩溃问题 2.我怎么能找出导致崩溃的原因。我使用-v 2来计算网址并将其记录在我的应用中。在这两种情况下，我都没有看到任何问题，项目在我的代码之外崩溃 3.我如何解决下面的unicode警告？

 Wapiti-2.2.1 (wapiti.sourceforge.net)
..............................
 Notice
========
This scan has been saved in the file C:\unzipped\wapiti-2.2.1\wapiti-2.2.1\src/s
cans/localhost:17357.xml
You can use it to perform attacks without scanning again the web site with the "
-k" parameter
[*] Loading modules :
        mod_crlf, mod_exec, mod_file, mod_sql, mod_xss, mod_backup, mod_htaccess
, mod_blindsql, mod_permanentxss, mod_nikto

[+] Launching module crlf

[+] Launching module exec

[+] Launching module file

[+] Launching module sql
C:\unzipped\wapiti-2.2.1\wapiti-2.2.1\src\attack\mod_sql.py:185: UnicodeWarning:
 Unicode equal comparison failed to convert both arguments to Unicode - interpre
ting them as being unequal
  if (page, tmp) not in self.attackedPOST:

[+] Launching module xss
Traceback (most recent call last):
  File "wapiti.py", line 449, in <module>
    wap.attack()
  File "wapiti.py", line 266, in attack
    x.attack(self.urls, self.forms)
  File "C:\unzipped\wapiti-2.2.1\wapiti-2.2.1\src\attack\attack.py", line 121, i
n attack
    self.attackGET(page, dictio, headers)
  File "C:\unzipped\wapiti-2.2.1\wapiti-2.2.1\src\attack\mod_xss.py", line 71, i
n attackGET
    self.findXSS(page, {}, "", code, "", payloads, headers["link_encoding"])
  File "C:\unzipped\wapiti-2.2.1\wapiti-2.2.1\src\attack\mod_xss.py", line 306,
in findXSS
    dat = self.HTTP.send(url).getPage()
  File "C:\unzipped\wapiti-2.2.1\wapiti-2.2.1\src\net\HTTP.py", line 94, in send

    info, data = self.h.request(target, headers = _headers)
  File "C:\unzipped\wapiti-2.2.1\wapiti-2.2.1\src\net\httplib2\__init__.py", lin
e 1084, in request
    (response, content) = self._request(conn, authority, uri, request_uri, metho
d, body, headers, redirections, cachekey)
  File "C:\unzipped\wapiti-2.2.1\wapiti-2.2.1\src\net\httplib2\__init__.py", lin
e 888, in _request
    (response, content) = self._conn_request(conn, request_uri, method, body, he
aders)
  File "C:\unzipped\wapiti-2.2.1\wapiti-2.2.1\src\net\httplib2\__init__.py", lin
e 853, in _conn_request
    response = conn.getresponse()
  File "C:\dev\bin\Python26\lib\httplib.py", line 974, in getresponse
    response.begin()
  File "C:\dev\bin\Python26\lib\httplib.py", line 391, in begin
    version, status, reason = self._read_status()
  File "C:\dev\bin\Python26\lib\httplib.py", line 349, in _read_status
    line = self.fp.readline()
  File "C:\dev\bin\Python26\lib\socket.py", line 397, in readline
    data = recv(1)
socket.error: [Errno 10054] An existing connection was forcibly closed by the re
mote host

Answer 1

Wapiti可能会使应用程序崩溃，因为它会占用您的大量应用程序。在进行XSS测试时跟踪了Wapiti堆栈，我认为xss测试不会导致应用程序崩溃。但是，通过提交大量1种类型的请求，这可能会导致DoS条件。您需要追踪Wapiti最后提出的要求。 Wapiti有一个冗长的模式，我认为它的-v它将打印出它所做的每个请求。一旦你有崩溃的文件，你应该手动审查它。

Wapiti的盲sql注入攻击模块使用mysql的基准（）函数 WILL DoS 你的mysql服务器，如果你在扫描整个网站时遇到问题，我建议你关掉这个。

wapiti崩溃了我的ASP.NET项目。为什么？我如何解决它？

1 个答案: