Question

注意：我不想触摸数据库中的任何数据。我正在谈论删除HTML表格。

此外，我尝试过使用＆＃34; .html（）＆＃34;和＆＃34; .remove（）＆＃34;在我的桌子上，但他们最终打破了格式，或者不允许任何信息显示。

我将尝试尽可能多地使用尽可能多的代码解释我的问题，所以如果遗漏任何内容请告诉我，我会添加它。

现在我有一个HTML页面，我有一张桌子。
此HTML表包含从数据库中提取的多行MYSQL数据。
在页面加载时，将获取初始数据并显示在表格中。
我在页面顶部有几个不同的排序选项，我试图根据创建日期，付费人员和已验证的内容对表格中的数据进行排序。（这些只是几个例子。

我希望能够在点击其中一个排序选项时清除表格，并让PHP重新查询数据库并提取已附加排序条件的信息。

查询有效，数据将添加到表中。但是，新的（已排序的）数据不是替换旧数据并显示已排序的数据，而是附加到表的顶部，从而保留旧数据。

我该如何解决这个问题？我只希望显示新的排序数据。

此if语句检查一个名为hasBeenSubmitted的下拉菜单是否有一个如果点击了它的选项，如果是，它会根据所选的选项执行以下操作。

if(checkValue($_POST['hasBeenSubmitted'])) {
switch($_POST['hasBeenSubmitted']) {
    case 'yes':
        $query1 = "SELECT *
FROM APPLICATION_Primary
INNER JOIN Application ON Application_primary.applicationId = Application.applicationId AND     hasBeenSubmitted = 1
INNER JOIN Applicant ON Applicant.applicantId = Application.applicantId
INNER JOIN APPLICATION_Degree ON Application.applicationId = APPLICATION_Degree.applicationId
INNER JOIN (SELECT DISTINCT (
department_code
), academic_programCode, department_nameFull
FROM  AcademicProgram) AS 
ac_program ON APPLICATION_Degree.academic_program = ac_program.department_code
INNER JOIN APPLICATION_Transaction ON Application.transactionId =     APPLICATION_Transaction.transactionId
ORDER BY Applicant.applicantId ASC";



//SOMEHOW CLEAR THE TABLE HERE?


//QUERY
         $updatedapplicants = $db->query($query1);
         populateTable($updatedapplicants);
        break;
    case 'no':
        $query1 = "SELECT *
FROM APPLICATION_Primary
INNER JOIN Application ON Application_primary.applicationId = Application.applicationId AND     hasBeenSubmitted = 0
INNER JOIN Applicant ON Applicant.applicantId = Application.applicantId
INNER JOIN APPLICATION_Degree ON Application.applicationId = APPLICATION_Degree.applicationId
INNER JOIN (SELECT DISTINCT (
department_code
), academic_programCode, department_nameFull
FROM  AcademicProgram) AS 
ac_program ON APPLICATION_Degree.academic_program = ac_program.department_code
INNER JOIN APPLICATION_Transaction ON Application.transactionId =     APPLICATION_Transaction.transactionId
ORDER BY Applicant.applicantId ASC";

     //SOMEHOW CLEAR THE TABLE HERE?

         //QUERY
         $updatedapplicants = $db->query($query1);
         populateTable($updatedapplicants);
        break;
}
}

这是populateTable（），它完全符合您的想法。它从申请人变量中获取信息并提取所需的列，并在表格中回显。

function populateTable($updatedapplicants) {

foreach($updatedapplicants as $applicant) {
$color = $color == 'light'? 'dark' : 'light';
?>
<tr
    class='<?php echo $color;?>'     id='applicant_data'>
<td style="text-align: center;"><?PHP echo '<input type="checkbox"  class="processed_check"     id="applicant-' . $applicant['applicant_id'] . '" ';
if($applicant['status'] == 1){
    echo "checked";
}
echo '>';
?></td>

<td><?php echo $applicant['applicantId']; ?></td>
<td><?php echo $applicant['isPayingOnline']; ?></td>
<td><?php echo ($applicant['hasBeenSubmitted'] == 1) ? 'yes' : 'no'; ?></td>

<!-- applicant info -->
<td><?php 
if($applicant['hasBeenSubmitted '] == 1) {
    $exDOB = explode("/", $applicant['date_of_birth']);
    $newDOB = $exDOB[0].$exDOB[1].$exDOB[2];
    $pdftitle = $applicant['applicationId']."_".$applicant['familyName']."_".$applicant['givenName']."_".$newDOB.".p    df";
    echo "<a href='getFile.php?FileName=" . $pdftitle . "&FileType=application' target='_blank'>" . $applicant['applicant_name'] . "</a>";
} else {
    echo $applicant['givenName']." ".$applicant['familyName'];
}
?></td>

<!-- academic info -->
<td><?php echo $applicant['academic_programCode'] . ' - ' . $applicant['department_nameFull']; ?></td>
<td><?php echo $applicant['submittedDate'] ?></td>
<td><?php echo $applicant['startSemester'] ?></td>
<td><?php echo $applicant['startYear'] ?></td>

<td><?php echo ($applicant['isCompleted'] == 'Y') ? "yes" : "no"; ?></td>
<td><?php echo $applicant['studentType'] ?></td>
<td><?php echo $applicant['academic_load'] ?></td>
<td><?php 
$email = $applicant['loginEmail'];
echo "<a href='mailto:$email'>$email</a>";
?></td>
<td><?php
if ($applicant['essayOldFileName']) {
    $exDOB = explode("/", $applicant['date_of_birth']);
    $newDOB = $exDOB[0].$exDOB[1].$exDOB[2];
    $ext = end(explode(".", $applicant['essayOldFileName']));
    $filename = "essay_".$applicant['applicantId']."_".$applicant['givenName']."_".$applicant['familyName']."_".$new    DOB.".".$ext;
    echo "<a href='getFile.php?FileName=$filename&FileType=essay' target='_blank'>Essay</a>";
}
?></td>
<td><?php
if($applicant['resumeOldFileName']) {
    $exDOB = explode("/", $applicant['date_of_birth']);
    $newDOB = $exDOB[0].$exDOB[1].$exDOB[2];
    $ext = end(explode(".", $applicant['resume_file_name']));
    $filename = "resume_".$applicant['applicant_id']."_".$applicant['given_name']."_".$applicant['family_name']."_".    $newDOB.".".$ext;
    echo "<a href='getFile.php?FileName=$filename&FileType=resume' target='_blank'>Resume</a>";
}
?></td>
</tr>

<?php }
}

谢谢，我感谢所有帮助。我真的被这个问题困住了。

HTML清除表格和插入数据

0 个答案: