Question

我将以下JSON字符串作为请求参数输入到我的grails控制器中。

{
    "loginName":"user1",
    "timesheetList":
    [
        {
            "periodBegin":"2014/10/12",
            "periodEnd":"2014/10/18",
            "timesheetRows":[
                {
                    "task":"Cleaning",
                    "description":"cleaning description",
                    "paycode":"payCode1"
                },
                {
                    "task":"painting",
                    "activityDescription":"painting description",
                    "paycode":"payCode2"
                }
            ]
        }
    ],
    "overallStatus":"SUCCESS"
}

如您所见，timesheetList可能包含多个元素。在这个（上面）的情况下，我们只有一个。所以，我希望它表现得像一个数组/列表。

然后我用下面的代码来解析它：

String saveJSON // This holds the above JSON string.

def jsonObject = grails.converters.JSON.parse(saveJSON) // No problem here. Returns a JSONObject. I checked the class type.
def jsonArray = jsonArray.timesheetList // No problem here. Returns a JSONArray. I checked the class type.
println "*** Size of jsonArray1: " + jsonArray1.size() // Returns size 1. It seemed fine as the above JSON string had only one timesheet in timesheetList

def timesheet1 = jsonArray[1] // This throws the JSONException, JSONArray[1] not found. I tried jsonArray.getJSONObject(1) and that throws the same exception.

基本上，我希望现在无缝迭代JSON字符串。有什么帮助吗？

Answer 1

首先关闭简化代码，使用request.JSON。然后request.JSON.list[ 0 ]应该正常工作

Grails：使用JSONArray / JSONObject解析JSON字符串

1 个答案: