我是iOS新手,我不明白为什么当我在单元格中点击我的项目时它无处可去。没有错误,没有任何错误。我的segue ID是Cell。我有一个可以正常添加数据的按钮,但是如果从表中选择的话,我试图更新数据。
这是我的.h
和.m
DerbyProTableViewController.h:
#import <UIKit/UIKit.h>
@interface DerbyProTableViewController : UITableViewController
@property (strong) NSMutableArray *racerarray;
@end
DerbyProTableViewController.m:
#import "DerbyProTableViewController.h"
#import "DerbyProDetailViewController.h"
@interface DerbyProTableViewController ()
@end
@implementation DerbyProTableViewController
- (NSManagedObjectContext *)managedObjectContext
{
NSManagedObjectContext *context = nil;
id delegate = [[UIApplication sharedApplication] delegate];
if ([delegate performSelector:@selector(managedObjectContext)]) {
context = [delegate managedObjectContext];
}
return context;
}
- (void)viewDidLoad
{
[super viewDidLoad];
[self.tableView registerClass:[UITableViewCell class] forCellReuseIdentifier:@"Cell"];
}
- (void)viewDidAppear:(BOOL)animated
{
[super viewDidAppear:animated];
// Fetch the devices from persistent data store
NSManagedObjectContext *managedObjectContext = [self managedObjectContext];
NSFetchRequest *fetchRequest = [[NSFetchRequest alloc] initWithEntityName:@"Racer"];
self.racerarray = [[managedObjectContext executeFetchRequest:fetchRequest error:nil] mutableCopy];
[self.tableView reloadData];
}
- (void)didReceiveMemoryWarning
{
[super didReceiveMemoryWarning];
// Dispose of any resources that can be recreated.
}
#pragma mark - Table view data source
- (NSInteger)numberOfSectionsInTableView:(UITableView *)tableView
{
// Return the number of sections.
return 1;
}
- (NSInteger)tableView:(UITableView *)tableView numberOfRowsInSection:(NSInteger)section
{
// Return the number of rows in the section.
return self.racerarray.count;
}
- (UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath
{
static NSString *CellIdentifier = @"Cell";
UITableViewCell *cell = [tableView dequeueReusableCellWithIdentifier:CellIdentifier forIndexPath:indexPath];
// Configure the cell...
NSManagedObject *device = [self.racerarray objectAtIndex:indexPath.row];
[cell.textLabel setText:[NSString stringWithFormat:@"%@ %@", [device valueForKey:@"lastname"], [device valueForKey:@"firstname"]]];
return cell;
}
// Override to support conditional editing of the table view.
- (BOOL)tableView:(UITableView *)tableView canEditRowAtIndexPath:(NSIndexPath *)indexPath
{
// Return NO if you do not want the specified item to be editable.
return YES;
}
// Override to support editing the table view.
- (void)tableView:(UITableView *)tableView commitEditingStyle:(UITableViewCellEditingStyle)editingStyle forRowAtIndexPath:(NSIndexPath *)indexPath
{
NSManagedObjectContext *context = [self managedObjectContext];
if (editingStyle == UITableViewCellEditingStyleDelete) {
// Delete object from database
[context deleteObject:[self.racerarray objectAtIndex:indexPath.row]];
NSError *error = nil;
if (![context save:&error]) {
NSLog(@"Can't Delete! %@ %@", error, [error localizedDescription]);
return;
}
// Remove device from table view
[self.racerarray removeObjectAtIndex:indexPath.row];
[self.tableView deleteRowsAtIndexPaths:[NSArray arrayWithObject:indexPath] withRowAnimation:UITableViewRowAnimationFade];
}
}
- (void)prepareForSegue:(UIStoryboardSegue *)segue sender:(id)sender
{
if ([[segue identifier] isEqualToString:@"updateracer"]){
NSManagedObject *selectedDevice = [self.racerarray objectAtIndex:[[self.tableView indexPathForSelectedRow] row]];
DerbyProDetailViewController *destinationViewController = segue.destinationViewController;
destinationViewController.derbyprodb = selectedDevice;
}
}
答案 0 :(得分:3)
我正在接受您粘贴的代码中所看到的内容。我不知道故事板中可能设置了什么,但是......
没有为UITableView对象指定委托或数据源。 UITableViewDelegate处理单元格选择。 一旦你设置了这样的代表:
[self.tableview setDelegate:self];
然后您需要实施:
- (void)tableView:(UITableView *)tableView didSelectRowAtIndexPath:(NSIndexPath *)indexPath;
像这样:
- (void)tableView:(UITableView *)tableView didSelectRowAtIndexPath:(NSIndexPath *)indexPath {
[self performSegueWithIdentifier:@"whateveryoursegueiscalled" sender:thecellyoutapped];
}
阅读Apple的tableview编程指南。
答案 1 :(得分:-2)
您可能无法在故事板中的“身份”检查器中添加课程。
在故事板中选择您的视图,然后单击identity ispector。确保Class字段不为空