Question

我有两个ListView和一个适配器用于前一个和将来的项目。

StepAdapter quoteStepAdapter = new StepAdapter(RequestDetail.this, 
                R.layout.lv_step, quoteInitiationStepsList);
ListView qouteStepListView = (ListView) findViewById(R.id.quote_step_list);
qouteStepListView.setAdapter(quoteStepAdapter);

List<Step> solutionDesignSteps = initSolutionDesignSteps();
StepAdapter solutionDesignStepAdapter = new StepAdapter(RequestDetail.this, 
                R.layout.lv_step, solutionDesignSteps);
ListView solutionDesignListView = (ListView) findViewById(R.id.solution_design_step_list);
solutionDesignListView.setAdapter(solutionDesignStepAdapter);

我知道solutionDesignSteps包含不同的项目。但是在屏幕和getView中我列出了相同的项目。

这里我只填写步骤列表（仅供测试）

private List<Step> initSolutionDesignSteps(){
        List<Step> steps = new ArrayList();     
        steps.add(new Step("desc2", 2, "Started", new Date("27 Feb 2014")));
        steps.add(new Step("desc3", 3, "", new Date("28 Feb 2014")));       
        steps.add(new Step("desc4", 4, "Started", new Date("02 Mar 2014")));
        steps.add(new Step("desc5", 5, "Started", new Date("02 Mar 2014")));        
        return steps;
    }

我的适配器类

private static class StepAdapter extends ArrayAdapter<Step> {

        private Context context;
        private int resourceId;
        private List<Step> stepsList;

        public StepAdapter(Context context, int resourceId, List<Step> steps) {
            super(context, resourceId, steps);
            this.context = context;
            this.resourceId = resourceId;
            this.stepsList = steps;
        }

        @Override
        public View getView(int position, View convertView, ViewGroup parent) {
            LayoutInflater layoutInflater = (LayoutInflater) context
                    .getSystemService(LAYOUT_INFLATER_SERVICE);
            View rowView = layoutInflater.inflate(resourceId, parent, false);

            Step step = stepsList.get(0);

            TextView orderedNumber = (TextView) rowView
                    .findViewById(R.id.step_number);
            orderedNumber.setText(step.getOrderedNumber() + ". ");

            TextView description = (TextView) rowView
                    .findViewById(R.id.step_description);
            description.setText(step.getDescription());

            Drawable drawable = null;
            Resources resources = context.getResources();
            if ("Complete".equals(step.getStatus())) {
                drawable = resources.getDrawable(R.drawable.ic_check);
            } else if ("Started".equals(step.getStatus())) {
                drawable = resources.getDrawable(R.drawable.ic_started);
            }

            if(drawable != null){
                ImageView stepStatus = (ImageView) rowView
                        .findViewById(R.id.step_status);
                stepStatus.setImageDrawable(drawable);
            }

            TextView stepUpdatedDate = (TextView) rowView
                    .findViewById(R.id.status_updated);
            SimpleDateFormat simpleDateFormat = new SimpleDateFormat(resources.getString(R.string.date_format));
            String stepUpdatedDateStr = simpleDateFormat.format(step
                    .getUpdatedDate());
            stepUpdatedDate.setText(stepUpdatedDateStr);

            return rowView;

        }

    }

你能帮我理解这个问题吗？

Answer 1

在适配器中，您似乎只使用相同的步骤对象Step step = stepsList.get(0); 它应该是Step step = stepsList.get(position);

之类的东西

Answer 2

替换

 Step step = stepsList.get(0);

与

 Step step = stepsList.get(position);

Android ListView显示相同的项目

2 个答案: