Question

我有一组rels，使用此

创建

MATCH (u:user)-[i:INTEREST]->(t:term)
WITH COLLECT([i,t]) AS its
RETURN its

并正确返回rels和nodes数组。另见http://console.neo4j.org/r/cw7saq

现在我想设置关系的属性，但是看不到我如何访问数组中的rels。试过这个，

MATCH (u:user)-[i:INTEREST]->(t:term)
WITH COLLECT([i,t]) AS its
FOREACH (it IN its |
         SET it[0].testprop=89292" )

但它返回错误

Error: Invalid input '[': expected an identifier character, node labels, a property map, a relationship pattern, '(', '.' or '=' (line 4, column 16)
"         SET it[0].testprop=89292" )"

任何人都知道这样做的正确语法是什么？

Answer 1

也不需要收集术语节点。请按以下步骤操作：

MATCH path=(u:user)-[i:INTEREST]->(t:term)
FOREACH (n IN rels(path) | set n.testprop=89292)

Answer 2

任何遇到OP提到的子集错误的人都可以用括号解决它：

MATCH (u:user)-[i:INTEREST]->(t:term)
WITH COLLECT([i,t]) AS its
FOREACH (it IN its |
     SET (it[0]).testprop=89292" )

在cypher收集的FOREACH

2 个答案: