Question

Goodday，

我在Android应用上有5个spinner s。这些spinner必须默认为在没有值的情况下启动00或者在DB中保存的值的substring(0,2)。

datasource = new Source(this); 
    datasource.open();

    List<Data> values = datasource.getAll(num);

    for (Data c: values)
    {
    d1 = c.getd1();
    d2 = c.getd2();
    d3 = c.getd3();
    d4 = c.getd4();
    d5 = c.getd5();
    }

    if (d1.isEmpty())
    {
    d1 = "00";  
    }

    if (d2.isEmpty())
    {
    d2 = "00";  
    }

    if (dev3.isEmpty())
    {
    dev3 = "00";    
    }

    if (dev4.isEmpty())
    {
    dev4 = "00";    
    }

    if (d5.isEmpty())
    {
    d5 = "00";  
    }

    Spinner location1 = (Spinner)findViewById(R.id.spind1);
    Spinner location2 = (Spinner)findViewById(R.id.spind2);
    Spinner location3 = (Spinner)findViewById(R.id.spind3);
    Spinner location4 = (Spinner)findViewById(R.id.spind4);
    Spinner location5 = (Spinner)findViewById(R.id.spind5);

    ArrayAdapter myAdap1 = (ArrayAdapter) location1.getAdapter();
    ArrayAdapter myAdap2 = (ArrayAdapter) location2.getAdapter();
    ArrayAdapter myAdap3 = (ArrayAdapter) location3.getAdapter();
    ArrayAdapter myAdap4 = (ArrayAdapter) location4.getAdapter();
    ArrayAdapter myAdap5 = (ArrayAdapter) location5.getAdapter();

    int spinnerPosition1 = myAdap1.getPosition(d1);
    int spinnerPosition2 = myAdap2.getPosition(d2);
    int spinnerPosition3 = myAdap3.getPosition(d3);
    int spinnerPosition4 = myAdap4.getPosition(d4);
    int spinnerPosition5 = myAdap5.getPosition(d5);

//set the default according to value
    location1.setSelection(spinnerPosition1);
    location2.setSelection(spinnerPosition2);
    location3.setSelection(spinnerPosition3);
    location4.setSelection(spinnerPosition4);
    location5.setSelection(spinnerPosition5);

问题是我只希望substring值获得spinner位置。例如，d1可以是＆＃34; 00＆＃34;，＆＃34; 01＆＃34;，＆＃34; 02＆＃34;，＆＃34; 03＆＃34;保存在数据库中，但spinner数组中的值为：

＆＃34; 00：无＆＃34; ＆＃34; 01：所有＆＃34; ＆＃34; 02：半＆＃34; ＆＃34; 03：季度＆＃34;

那么如何使用：int spinnerPosition1 = myAdap1.getPosition(d1);显然会检查＆＃34; 01＆＃34; ！=＆＃34; 01：全部＆＃34;。所以我需要substring spinner字符串？有谁能够帮我？

Answer 1

str.substring(0, 2);

使用子字符串作为前两个字符。

Answer 2

要检查substring，请尝试以下操作：

str.subString(0,2).equalsIgnoreCase("01")

str是spinner字符串。

来自字符串substring的android spinner getPosition（）

2 个答案: