SQL Server

Question

我有一个包含account numbers和card numbers的数据库。我将这些文件与update的任何卡号匹配到帐号，以便我只使用帐号。

我创建了一个视图，将表连接到帐户/卡片数据库以返回Table ID和相关的帐号，现在我需要更新ID与帐号匹配的记录。

这是Sales_Import表，其中account number字段需要更新：

LeadID  AccountNumber
147         5807811235
150         5807811326
185         7006100100007267039

这是RetrieveAccountNumber表，我需要从中更新：

LeadID  AccountNumber
147         7006100100007266957
150         7006100100007267039

我试过以下，但到目前为止没有运气：

UPDATE [Sales_Lead].[dbo].[Sales_Import] 
SET    [AccountNumber] = (SELECT RetrieveAccountNumber.AccountNumber 
                          FROM   RetrieveAccountNumber 
                          WHERE  [Sales_Lead].[dbo].[Sales_Import]. LeadID = 
                                                RetrieveAccountNumber.LeadID)

它会将卡号更新为帐号，但帐号会被NULL

替换

Answer 1

我相信带有UPDATE FROM的{{1}}会有所帮助：

MS SQL

JOIN

MySQL和MariaDB

UPDATE
    Sales_Import
SET
    Sales_Import.AccountNumber = RAN.AccountNumber
FROM
    Sales_Import SI
INNER JOIN
    RetrieveAccountNumber RAN
ON 
    SI.LeadID = RAN.LeadID;

Answer 2

将内容从一个表复制到另一个表的简单方法如下：

UPDATE table2 
SET table2.col1 = table1.col1, 
table2.col2 = table1.col2,
...
FROM table1, table2 
WHERE table1.memberid = table2.memberid

您还可以添加条件以复制特定数据。

Answer 3

对于SQL Server 2008 +使用MERGE而不是专有的UPDATE ... FROM语法具有一定的吸引力。

除了作为标准SQL并因此更具可移植性之外，如果源端存在多个连接行（因此在更新中使用多个可能的不同值）而不是最终的，它也会引发错误结果是不确定的。

MERGE INTO Sales_Import
   USING RetrieveAccountNumber
      ON Sales_Import.LeadID = RetrieveAccountNumber.LeadID
WHEN MATCHED THEN
   UPDATE 
      SET AccountNumber = RetrieveAccountNumber.AccountNumber;

不幸的是，选择使用哪种方法可能不会仅仅归结为首选风格。 SQL Server中MERGE的实现受到各种错误的影响。 Aaron Bertrand编制了一份the reported ones here列表。

Answer 4

未来开发人员的通用答案。

SQL Server

UPDATE 
     t1
SET 
     t1.column = t2.column
FROM 
     Table1 t1 
     INNER JOIN Table2 t2 
     ON t1.id = t2.id;

Oracle（和SQL Server）

UPDATE 
     t1
SET 
     t1.colmun = t2.column 
FROM 
     Table1 t1, 
     Table2 t2 
WHERE 
     t1.ID = t2.ID;

的MySQL

UPDATE 
     Table1 t1, 
     Table2 t2
SET 
     t1.column = t2.column 
WHERE
     t1.ID = t2.ID;

Answer 5

似乎你正在使用MSSQL，如果我没记错的话，就这样做了：

UPDATE [Sales_Lead].[dbo].[Sales_Import] SET [AccountNumber] = 
RetrieveAccountNumber.AccountNumber 
FROM RetrieveAccountNumber 
WHERE [Sales_Lead].[dbo].[Sales_Import].LeadID = RetrieveAccountNumber.LeadID

Answer 6

对于foo.new中null的{{1}}行，foo中没有匹配键的行，我遇到了同样的问题。我在Oracle中做了类似的事情：

update foo
set    foo.new = (select bar.new
                  from bar 
                  where foo.key = bar.key)
where exists (select 1
              from bar
              where foo.key = bar.key)

Answer 7

对于PostgreSQL：

UPDATE Sales_Import SI
SET AccountNumber = RAN.AccountNumber
FROM RetrieveAccountNumber RAN
WHERE RAN.LeadID = SI.LeadID;

Answer 8

对于运行良好的MySql：

UPDATE
    Sales_Import SI,RetrieveAccountNumber RAN
SET
    SI.AccountNumber = RAN.AccountNumber
WHERE
    SI.LeadID = RAN.LeadID

Answer 9

感谢您的回复。我找到了解决方案。

UPDATE Sales_Import 
SET    AccountNumber = (SELECT RetrieveAccountNumber.AccountNumber 
                          FROM   RetrieveAccountNumber 
                          WHERE  Sales_Import.leadid =RetrieveAccountNumber.LeadID) 
WHERE Sales_Import.leadid = (SELECT  RetrieveAccountNumber.LeadID 
                             FROM   RetrieveAccountNumber 
                             WHERE  Sales_Import.leadid = RetrieveAccountNumber.LeadID)

Answer 10

这是在SQL Server中对我有用的东西：

UPDATE [AspNetUsers] SET

[AspNetUsers].[OrganizationId] = [UserProfile].[OrganizationId],
[AspNetUsers].[Name] = [UserProfile].[Name]

FROM [AspNetUsers], [UserProfile]
WHERE [AspNetUsers].[Id] = [UserProfile].[Id];

Answer 11

从一个表更新到另一个 id 匹配的表

UPDATE 
     TABLE1 t1, 
     TABLE2 t2
SET 
     t1.column_name = t2.column_name 
WHERE
     t1.id = t2.id;

Answer 12

使用以下查询块根据ID更新Table1和Table2：

UPDATE Sales_Import, RetrieveAccountNumber 
SET Sales_Import.AccountNumber = RetrieveAccountNumber.AccountNumber 
where Sales_Import.LeadID = RetrieveAccountNumber.LeadID;

这是解决此问题的最简单方法。

Answer 13

以下SQL有人建议，在SQL Server中不起作用。这种语法让我想起了我的旧学校课程：

UPDATE table2 
SET table2.col1 = table1.col1, 
table2.col2 = table1.col2,
...
FROM table1, table2 
WHERE table1.memberid = table2.memberid

不建议使用NOT IN或NOT EXISTS的所有其他查询。由于OP将整个数据集与较小的子集进行比较，因此会显示NULL，然后会出现匹配问题。必须使用JOIN通过使用正确的NOT IN编写正确的SQL而不是避免躲避问题来解决此问题。在这种情况下，您可能会使用NOT IN或NOT EXISTS来解决其他问题。

我对顶级投票的投票，这是通过加入SQL Server来更新基于另一个表的表的传统方式。就像我说的，你不能在SQL Server中的同一UPDATE语句中使用两个表，除非你先加入它们。

Answer 14

在同一张表中更新：

  DECLARE @TB1 TABLE
    (
        No Int
        ,Name NVarchar(50)
        ,linkNo int
    )

    DECLARE @TB2 TABLE
    (
        No Int
        ,Name NVarchar(50)
        ,linkNo int
    )

    INSERT INTO @TB1 VALUES(1,'changed person data',  0);
    INSERT INTO @TB1 VALUES(2,'old linked data of person', 1);

INSERT INTO @TB2 SELECT * FROM @TB1 WHERE linkNo = 0


SELECT * FROM @TB1
SELECT * FROM @TB2


    UPDATE @TB1 
        SET Name = T2.Name
    FROM        @TB1 T1
    INNER JOIN  @TB2 T2 ON T2.No = T1.linkNo

    SELECT * FROM @TB1

Answer 15

它适用于postgresql

UPDATE application
SET omts_received_date = (
    SELECT
        date_created
    FROM
        application_history
    WHERE
        application.id = application_history.application_id
    AND application_history.application_status_id = 8
);

Answer 16

这是 Mysql 和 Maria DB 所见过的最简单和最好的

UPDATE table2, table1 SET table2.by_department = table1.department WHERE table1.id = table2.by_id

注意：如果您根据您的 Mysql/Maria DB 版本遇到以下错误“错误代码：1175。您正在使用安全更新模式，并且您尝试更新没有使用 KEY 列的 WHERE 的表要禁用安全模式, 切换首选项中的选项"

然后像这样运行代码

SET SQL_SAFE_UPDATES=0;
UPDATE table2, table1 SET table2.by_department = table1.department WHERE table1.id = table2.by_id

Answer 17

MS Sql

UPDATE  c4 SET Price=cp.Price*p.FactorRate FROM TableNamea_A c4
inner join TableNamea_B p on c4.Calcid=p.calcid 
inner join TableNamea_A cp on c4.Calcid=cp.calcid 
WHERE c4..Name='MyName';

Oracle 11g

        MERGE INTO  TableNamea_A u 
        using
        (
                SELECT c4.TableName_A_ID,(cp.Price*p.FactorRate) as CalcTot 
                FROM TableNamea_A c4
                inner join TableNamea_B p on c4.Calcid=p.calcid 
                inner join TableNamea_A cp on c4.Calcid=cp.calcid 
                WHERE p.Name='MyName' 
        )  rt
        on (u.TableNamea_A_ID=rt.TableNamea_B_ID)
        WHEN MATCHED THEN
        Update set Price=CalcTot  ;

Answer 18

我认为这是一个简单的例子，可能有人会让它变得更容易，

        DECLARE @TB1 TABLE
        (
            No Int
            ,Name NVarchar(50)
        )

        DECLARE @TB2 TABLE
        (
            No Int
            ,Name NVarchar(50)
        )

        INSERT INTO @TB1 VALUES(1,'asdf');
        INSERT INTO @TB1 VALUES(2,'awerq');


        INSERT INTO @TB2 VALUES(1,';oiup');
        INSERT INTO @TB2 VALUES(2,'lkjhj');

        SELECT * FROM @TB1

        UPDATE @TB1 SET Name =S.Name
        FROM @TB1 T
        INNER JOIN @TB2 S
                ON S.No = T.No

        SELECT * FROM @TB1

Answer 19

MYSQL（这是我根据主键 reasonId 等价性恢复所有特定列 id 值的首选方法）

UPDATE `site` AS destination  
INNER JOIN `site_copy` AS backupOnTuesday 
      ON backupOnTuesday.`id` = destination.`id`
SET destdestination.`reasonId` = backupOnTuesday.`reasonId`

Answer 20

Oracle 11g

merge into Sales_Import
using RetrieveAccountNumber
on (Sales_Import.LeadId = RetrieveAccountNumber.LeadId)
when matched then update set Sales_Import.AccountNumber = RetrieveAccountNumber.AccountNumber;

Answer 21

如果表位于不同的数据库中。（SQLserver）

update database1..Ciudad
set CiudadDistrito=c2.CiudadDistrito

FROM database1..Ciudad c1
 inner join 
  database2..Ciudad c2 on c2.CiudadID=c1.CiudadID

Answer 22

试试这个：

UPDATE
    Table_A
SET
    Table_A.AccountNumber = Table_B.AccountNumber ,
FROM
    dbo.Sales_Import AS Table_A
    INNER JOIN dbo.RetrieveAccountNumber AS Table_B
        ON Table_A.LeadID = Table_B.LeadID 
WHERE
    Table_A.LeadID = Table_B.LeadID

Answer 23

这将允许您根据另一个表中找不到的列值更新表。

    UPDATE table1 SET table1.column = 'some_new_val' WHERE table1.id IN (
            SELECT * 
            FROM (
                    SELECT table1.id
                    FROM  table1 
                    LEFT JOIN table2 ON ( table2.column = table1.column ) 
                    WHERE table1.column = 'some_expected_val'
                    AND table12.column IS NULL
            ) AS Xalias
    )

这将根据在两个表中找到的列值更新表。

    UPDATE table1 SET table1.column = 'some_new_val' WHERE table1.id IN (
            SELECT * 
            FROM (
                    SELECT table1.id
                    FROM  table1 
                    JOIN table2 ON ( table2.column = table1.column ) 
                    WHERE table1.column = 'some_expected_val'
            ) AS Xalias
    )

Answer 24

我想补充一点。

不要使用相同的值更新值，它会产生额外的日志记录和不必要的开销。请参阅下面的示例 - 尽管链接为3，它仍将仅对2条记录执行更新。

DROP TABLE #TMP1
DROP TABLE #TMP2
CREATE TABLE #TMP1(LeadID Int,AccountNumber NVarchar(50))
CREATE TABLE #TMP2(LeadID Int,AccountNumber NVarchar(50))

INSERT INTO #TMP1 VALUES
(147,'5807811235')
,(150,'5807811326')
,(185,'7006100100007267039');

INSERT INTO #TMP2 VALUES
(147,'7006100100007266957')
,(150,'7006100100007267039')
,(185,'7006100100007267039');

UPDATE A
SET A.AccountNumber = B.AccountNumber
FROM
    #TMP1 A 
        INNER JOIN #TMP2 B
        ON
        A.LeadID = B.LeadID
WHERE
    A.AccountNumber <> B.AccountNumber  --DON'T OVERWRITE A VALUE WITH THE SAME VALUE

SELECT * FROM #TMP1

Answer 25

如果以上答案不适合您，请尝试此

Update Sales_Import A left join RetrieveAccountNumber B on A.LeadID = B.LeadID
Set A.AccountNumber = B.AccountNumber
where A.LeadID = B.LeadID

基于ID匹配从一个表到另一个表的SQL更新

25 个答案:

MS SQL

MySQL和MariaDB

SQL Server

Oracle（和SQL Server）

的MySQL