我的代码中的所有内容都在运行,直到3行感叹号。它打印出斐波那契序列,直到用户输入的限制为序列停止的位置。但在3行感叹号之后,我希望它使用if if then语句来打印一个字符串。但是当我运行它时,由于某种原因它不打印该字符串。所以错误就在感叹号之后的某个地方。我只是不确定是什么问题。如果(J> = 2584)然后你打印这个语句,如果(J> = 1597)然后你打印这个,依此类推,我想用更多的if if语句来做这个。谢谢你的帮助
.section ".data"
prompt: .asciz "\nEnter a limit on the largest number to be displayed: "
format: .asciz "%d"
format2: .asciz "%d "
myString: .asciz "\n1 " !print leading 1
myString2: .asciz "\n" !double space
string: .asciz "\nThe last number %d is divisible by %d\n""
prompt2: .asciz "\nDo you want to print a different sequence (Y/N): "
format3: .asciz "%s"
noString: .asciz "\nGoodbye.\n"
NOstring: .asciz "\nGoodbye.\n"
TESTSTRING: .asciz "You entered the character: %s\n"
input2: .asciz " "
.align 4
input: .word 0
nl: .asciz "\n"
! input2: .byte 0
! nl2: .asciz "\n"
define(f, l0)
define(i, l1)
define(j, l2)
define(g1, l3)
define(g2, l4)
define(g3, l5)
.align 4
.section ".text"
.global main
main:
save %sp, -96, %sp
!BIGLOOP:
clr %f
mov 1, %j
clr %i
set prompt, %o0 !point o0 to the prompt
call printf !call printf to print the prompt
nop
set format, %o0 !address of the format
set input, %o1 !address of the location for the max
set nl, %o2
call scanf !reads user input, coverts to a
nop !number and stores at the memory referenced by input
set format2, %o0
set input, %o1
ld [%o1], %o1 !userInput loaded into o1
mov %o1, %g1 !g1 = user input
set myString, %o0 !print leading 1
call printf
nop
test:
add %i, %j, %f !f=i+j
cmp %f, %g1 !while(f<=userInput)
bg done
nop
mov %j, %i !i=j
mov %f, %j !j=f
mov %j, %o1 !%o1=j
set format2, %o0
call printf
nop
mov %j, %g2
ba test
nop
done:
set myString2, %o0 !double space
call printf
nop
!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
!divisible
!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
set 1, %o2
ctz_loop:
andcc %g2, %o2, %g0
bne ctz_end
nop
ba ctz_loop
add %o2, %o2, %o2
ctz_end:
set string, %o0
mov %g2, %o1
call printf
nop
!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
! Do you want to print another sequence
!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
! invalidloop:
set prompt2, %o0 !do you want to print a different sequence
call printf
nop
set format3, %o0
set input2, %o1
call scanf
nop
set input2, %o1 <<<------------------------
ldub [%o1], %g3 !loading user answer to %g3
set TESTSTRING, %o0 !!!!!!!TestString
mov %g3, %o1 !!!!!!!TestStromg
set input2, %o1 !!!!!!!
call printf !!!!!!!
nop !!!!!!!
/*
cmp %g3, "y" !comparing answer to y
bne YES
nop
ba BIGLOOP !loop back to the beginning of the program
nop
YES:
cmp %g3, "Y" !comparing answer to Y
bne no
nop
ba BIGLOOP !loop baack to the beginning of the program
nop
no:
cmp %g3, "n" !comparing answer to n
bne NO
nop
set noString, %o0
call printf
nop
ba finish
nop
NO:
cmp %g3, "N" !comparing answer to N
bne invalid
nop
set NOstring, %o0
call printf
nop
ba finish
nop
invalid: !if neither Y,y,N,n was answered then it should ask if you still want to print another sequence again until the correct is chosen
ba invalidloop
nop
finish:
*/
ret
restore
!!!ERROR!!!!
!!!!!!!!!!!!
!!!ERROR!!!!
!Undefined first referenced
!symbol in file
!invalid /var/tmp//cc87QWAM.o
!BIGLOOP /var/tmp//cc87QWAM.o
!ld: fatal: Symbol referencing errors. No output written to mai4
!collect2: ld returned 1 exit status
答案 0 :(得分:0)
知道要解决的真正问题是打印最大的二次幂除数,这里有一个可能的算法:for(mask = 1; (mask & x) == 0; mask += mask);
程序集版本可能如下所示:
string: .asciz "\nThe last number %d is divisible by %d\n"
...
set 1, %o2 ! mask
ctz_loop:
andcc %g2, %o2, %g0
bne ctz_end
nop
ba ctz_loop
add %o2, %o2, %o2 ! next bit
ctz_end:
set string, %o0
mov %g2, %o1
call printf
nop