Question

A）我有一张医生表。每位医生都有一个独特的用户名，以及评级和专业。还有一张手术表。它包含（除其他外）具有医生唯一用户名的属性。它不是唯一的。

我正在尝试创建一个显示每个专业的表格。数据：

Speciality |   Avg. Rating for Each Speciality | # of surgeries performed by Speciality

（第一栏只是专业名称）

到目前为止我最好的：

 SELECT D.Speciality,t1.Avg, t0.CPT FROM DOCTOR as D 
  INNER JOIN(
    SELECT AVG(AvgRating) as Avg, Speciality
    FROM Doctors as D1
    GROUP BY D1.Speciality 
) as t1 ON D.Speciality=t1.Speciality
INNER JOIN(
    SELECT COUNT(CPT) as CPT, Speciality
    FROM PERFORM_SURGERY AS P
    GROUP BY P.Speciality
    )t0 ON t0.SPECIALITY=D.SPECIALITY
;

B） doctor 表包含唯一的用户名和非唯一的名称。还有一个处方表。它包含医生的用户名和患者的用户名。现在还有3个我们需要的表。一个是 Req_surgery ，手术和访问。 Req_surgery 包含Doctor的用户名和CPT（CPT是唯一的）。手术表有一个CPT的主键，它还包含手术费用。访问包含医生的用户名和患者的用户名以及访问费用。

我想要一张表格：

Doctor Name  | No of Patients Seen | No of Prescriptions written | Total Billing

列出每个医生的姓名和所需信息。

到目前为止，我有：

SELECT t1.name, t3.Visits, t2.Prescriptions, t4.money
    FROM DOCTOR as D
        INNER JOIN(
            SELECT (FName + LName) as name, Username
            FROM DOCTOR
        ) t1 ON t1.userName=D.username
        INNER JOIN(
            SELECT DUsername, COUNT(DateVisit) AS Prescriptions
            FROM PRESCRIPTION
            WHERE MONTH(DateVisit) = $month
            AND YEAR(DateVisit)=$year
        )t2 ON D.Username = t2.DUsername
        INNER JOIN(
            SELECT COUNT(DATEVISIT) as Visits, DUsername
            FROM VISIT as V
            WHERE MONTH(DateVisit) = $month
            AND YEAR(DateVisit)=$year
        )t3 ON D.Username=t3=DUsername

我甚至没有完成，因为（a）我知道我的错误，我不知道如何解决它，（b）我不知道如何计算每位医生的收入。 / p>

Doctor拥有Username的主键。手术是CPT的主要关键。 Req_Surgery具有引用Doctor（用户名）的Doctor's Username（以下称DU）的外键。

Answer 1

SELECT (FName + LName) as name, t3.Visits, t2.Prescriptions, t4.money
    FROM DOCTOR as D
        INNER JOIN(
            SELECT DUsername, COUNT(DateVisit) AS Prescriptions
            FROM PRESCRIPTION
            WHERE MONTH(DateVisit) = $month
            AND YEAR(DateVisit)=$year
            GROUP BY DUsername
        )t2 ON D.Username = t2.DUsername
        INNER JOIN(
            SELECT COUNT(DATEVISIT) as Visits, DUsername
            FROM VISIT as V
            WHERE MONTH(DateVisit) = $month
            AND YEAR(DateVisit)=$year
            GROUP BY DUsername
        )t3 ON D.Username=t3.DUsername

我添加了DUsername分组以获取每位医生的数字。我也删除了t1，因为实际上它与D

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