Question

我无法从JSP导航到我的控制器。我错过了什么？我的错误状态为404。

这是我的index.html

<!DOCTYPE html>
<html>
<head>
<meta charset="ISO-8859-1">
<title>WELCOME PAGE</title>
</head>
<body>

<h1>WELCOME TO NUTS </h1>
<br/>
<form action="remember.html">

    <input type="submit" value="GET STARTED"> 
</form>

</body>
</html>

这是我的控制器------------------------------------------- ----

@Controller
public class ProductController {



     @RequestMapping(value = "/remember")
      public String list(Model model) {
         ServiceFacade facade = new ServiceFacadeImpl();
         List<Product> products = facade.getAllProducts();
         model.addAttribute("products", products);
         return "/jsp/LoginPage";
     }



}

这是web.xml ----------------------------------------- ---------

   <?xml version="1.0" encoding="UTF-8"?>
    <web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" id="WebApp_ID" version="2.5">
      <display-name>NutsAboutCandyWebProject</display-name>
      <welcome-file-list>
        <welcome-file>index.html</welcome-file>
        <welcome-file>index.jsp</welcome-file>
      </welcome-file-list>

          <servlet>
            <servlet-name>appServlet</servlet-name>
            <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
            <init-param>
              <param-name>contextConfigLocation</param-name>
              <param-value>/WEB-INF/servlet-context.xml</param-value>
            </init-param>
            <load-on-startup>1</load-on-startup>
          </servlet>
</web-app>

这是我的servlet-context.xml ----------------------------------

<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
  xmlns:mvc="http://www.springframework.org/schema/mvc" xmlns:beans="http://www.springframework.org/schema/beans"
  xmlns:context="http://www.springframework.org/schema/context" xmlns:tx="http://www.springframework.org/schema/tx"
  xsi:schemaLocation="http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc-3.2.xsd
    http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd
    http://www.springframework.org/schema/tx http://www.springframework.org/schema/tx/spring-tx-3.2.xsd
    http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-3.2.xsd">

  <!-- Enable @Controller annotation support -->
  <mvc:annotation-driven />

  <!-- Map simple view name such as "test" into /WEB-INF/test.jsp -->
  <bean class="org.springframework.web.servlet.view.InternalResourceViewResolver">
    <property name="prefix" value="/jsp" />
    <property name="suffix" value=".jsp" />
  </bean>

  <!-- Scan classpath for annotations (eg: @Service, @Repository etc) -->
  <context:component-scan base-package="com.nutsaboutcandywebproject.controller"/>

  <!-- JDBC Data Source. It is assumed you have MySQL running on localhost port 3306 with 
       username root and blank password. Change below if it's not the case -->
  <bean id="myDataSource" class="org.apache.commons.dbcp.BasicDataSource" destroy-method="close">
    <property name="driverClassName" value="com.mysql.jdbc.Driver"/>
    <property name="url" value="jdbc:mysql://localhost:3306/db_nutsaboutcandy"/>
    <property name="username" value="root"/>
    <property name="password" value=""/>
    <property name="validationQuery" value="SELECT 1"/>
  </bean>

  <!-- Hibernate Session Factory -->
  <bean id="mySessionFactory" class="org.springframework.orm.hibernate4.LocalSessionFactoryBean">
    <property name="dataSource" ref="myDataSource"/>
    <property name="packagesToScan">
      <array>
        <value>com.nutsaboutcandywebproject.model</value>
      </array>
    </property>
    <property name="hibernateProperties">
      <value>
        hibernate.dialect=org.hibernate.dialect.MySQLDialect
      </value>
    </property>
  </bean>

  <!-- Hibernate Transaction Manager -->
  <!-- <bean id="transactionManager" class="org.springframework.orm.hibernate4.HibernateTransactionManager">
    <property name="sessionFactory" ref="mySessionFactory"/>
  </bean> -->

  <!-- Activates annotation based transaction management -->
  <!-- <tx:annotation-driven transaction-manager="transactionManager"/> -->
</beans>

编辑1：

web.xml配置

<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" id="WebApp_ID" version="2.5">
  <display-name>NutsAboutCandyWebProject</display-name>

  <servlet>
    <servlet-name>appServlet</servlet-name>
    <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
    <init-param>
      <param-name>contextConfigLocation</param-name>
      <param-value>/WEB-INF/servlet-context.xml</param-value>
    </init-param>
    <load-on-startup>1</load-on-startup>
  </servlet>
 <servlet-mapping>
    <servlet-name>appServlet</servlet-name>
    <url-pattern>/</url-pattern>
 </servlet-mapping>


</web-app>

servlet的context.xml中

  <?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
  xmlns:mvc="http://www.springframework.org/schema/mvc" xmlns:beans="http://www.springframework.org/schema/beans"
  xmlns:context="http://www.springframework.org/schema/context" xmlns:tx="http://www.springframework.org/schema/tx"
  xsi:schemaLocation="http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc-3.2.xsd
    http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd
    http://www.springframework.org/schema/tx http://www.springframework.org/schema/tx/spring-tx-3.2.xsd
    http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-3.2.xsd">

  <!-- Enable @Controller annotation support -->
  <mvc:annotation-driven />

  <!-- Map simple view name such as "test" into /WEB-INF/test.jsp -->
  <beans:bean   class="org.springframework.web.servlet.view.InternalResourceViewResolver">      
        <beans:property name="prefix" value="/" />      
        <beans:property name="suffix" value=".jsp" />   
  </beans:bean>

  <!-- Scan classpath for annotations (eg: @Service, @Repository etc) -->
  <context:component-scan base-package="com.nutsaboutcandywebproject.controller"/>

  <!-- JDBC Data Source. It is assumed you have MySQL running on localhost port 3306 with 
       username root and blank password. Change below if it's not the case -->
  <bean id="myDataSource" class="org.apache.commons.dbcp.BasicDataSource" destroy-method="close">
    <property name="driverClassName" value="com.mysql.jdbc.Driver"/>
    <property name="url" value="jdbc:mysql://localhost:3306/db_nutsaboutcandy"/>
    <property name="username" value="root"/>
    <property name="password" value=""/>
    <property name="validationQuery" value="SELECT 1"/>
  </bean>

  <!-- Hibernate Session Factory -->
  <bean id="mySessionFactory" class="org.springframework.orm.hibernate4.LocalSessionFactoryBean">
    <property name="dataSource" ref="myDataSource"/>
    <property name="packagesToScan">
      <array>
        <value>com.nutsaboutcandywebproject.model</value>
      </array>
    </property>
    <property name="hibernateProperties">
      <value>
        hibernate.dialect=org.hibernate.dialect.MySQLDialect
      </value>
    </property>
  </bean>

  <!-- Hibernate Transaction Manager -->
  <!--  <bean id="transactionManager" class="org.springframework.orm.hibernate4.HibernateTransactionManager">
    <property name="sessionFactory" ref="mySessionFactory"/>
  </bean>  -->

  <!-- Activates annotation based transaction management -->
  <!--  <tx:annotation-driven transaction-manager="transactionManager"/>  -->
</beans>

Answer 1

您要返回的值是“/ jsp / LoginPage”; 这意味着，你的控制器会说，“嘿，我已经完成了我的操作并返回了查看页面LoginPage”，所以现在，你的视图解析器的工作是添加适当的后缀并渲染它。

现在，你有没有在servlet-context.xml文件中声明一个视图解析器？ 2.如果你声明它，你不必指定“/ jsp /”，你可以在视图解析器中添加前缀。

另外，我发现你发送的是action =“remember.html”，你的控制器正在寻找“/ remember”。两者都不同。意思是，你必须写一些像“form action =”/ remember“” 这意味着，/ remember是一个终点。不是一个HTML页面。

Answer 2

除非您没有向我们展示，否则您尚未映射您的DispatcherServlet以处理任何请求。

你只有

<servlet>
    <servlet-name>appServlet</servlet-name>
    <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
    <init-param>
        <param-name>contextConfigLocation</param-name>
        <param-value>/WEB-INF/servlet-context.xml</param-value>
    </init-param>
    <load-on-startup>1</load-on-startup>
</servlet>

声明Servlet，但没有别的。

你需要一个映射，比如

<servlet-mapping>
    <servlet-name>appServlet</servlet-name>
    <url-pattern>*.html</url-pattern>
</servlet-mapping>

从jsp导航到控制器的问题

2 个答案: