Question

我需要帮助来确定如何重建gtk.stack的元素。

假设孩子是一个包含可能必须以多种方式重建的信息的gtk.box，因为重建应该完成？

def refresh_take(self):
    self.take_container.destroy()
    #Reconstructed container
    self.take_container = Gtk.Box(orientation=Gtk.Orientation.VERTICAL)
    #Reconstructed Top label
    hbox = Gtk.Box(orientation=Gtk.Orientation.HORIZONTAL)
    label = Gtk.Label("For take:", xalign=0)
    self.take_container.pack_start(label, False, False, 10)

    get_ready = self.database.get_tomas_ready()
    listbox = Gtk.ListBox()
    listbox.set_selection_mode(Gtk.SelectionMode.NONE)
    #Reconstructed First list
    counter = 0
    for list_element in get_ready[0]:
        self.create_med_dialog(list_element[0])
        row = Gtk.ListBoxRow()
        hbox = Gtk.Box(orientation=Gtk.Orientation.HORIZONTAL, spacing=50)
        row.add(hbox)
        vbox = Gtk.Box(orientation=Gtk.Orientation.VERTICAL)
        hbox.pack_start(vbox, True, True, 0)
        if list_element[4] in range(10):
            minutes = '0' + str(list_element[4])
        else:
            minutes = list_element[4]
        tempo = (str(get_ready[1][counter]) + ":" + str(minutes) + "H")

        Pill = Gtk.Label(tempo + "\t" + list_element[0] , xalign=0)
        vbox.pack_start(Pill, True, True, 0)
        if counter == 0:
            button = Gtk.Button(label="Take")
            self.demanded_pill = list_element[0]
            button.connect("clicked", self.demand_pill)
            hbox.pack_start(button, False, True, 0)

        listbox.add(row)

        self.take_container.pack_start(listbox, False, False, 0)
        counter = counter + 1

    #The second label is reconstructed
    hbox = Gtk.Box(orientation=Gtk.Orientation.HORIZONTAL)
    info_label = Gtk.Label("Next Pill:", xalign=0)
    self.take_container.pack_start(info_label, False, False, 10)

    get_next = self.database.get_tomas_next()
    listbox = Gtk.ListBox()
    listbox.set_selection_mode(Gtk.SelectionMode.NONE)
    #The second list is reconstructed
    counter = 0
    for list_element in get_next[0]:
        row = Gtk.ListBoxRow()
        hbox = Gtk.Box(orientation=Gtk.Orientation.HORIZONTAL, spacing=50)
        row.add(hbox)
        vbox = Gtk.Box(orientation=Gtk.Orientation.VERTICAL)
        hbox.pack_start(vbox, True, True, 0)

        if list_element[4] in range(10):
            minutes = '0' + str(list_element[4])
        else:
            minutes = list_element[4]
        Pill = Gtk.Label(list_element[0], xalign=0)
        vbox.pack_start(Pill, True, True, 0)
        label = Gtk.Label(str(get_next[1][counter])
        + ":" + str(minutes) + "H")
        hbox.pack_start(label, False, True, 0)
        listbox.add(row)
        counter = counter + 1

    self.take_container.pack_start(listbox, False, False, 0)
    self.take_container.set_visible(True)
    self.stack.add_named(self.take_container, "Takes")

当我的堆栈刷新时，所有内容都会消失，但我希望他们在销毁后再次创建标签。

Answer 1

从代码片段看，您似乎没有将创建的小部件添加到任何容器中。除非您在其他地方执行此操作，否则listbox和self.take_container已创建，但从未添加到任何容器中。

如何重建gtk.stack

1 个答案: