Question

我有一个带有一堆数字的输入文件，例如：

3 7 10 21 8 4 9 2

我写了一些代码来记录最高和最低值：

#include<stdio.h>
   main(){
    int low;
    int high;
    int current;
    char c;
    scanf("%i", &low);
    scanf("%i", &high);
    while((c=getchar())!= '\n'){
     scanf("%i", &current);
     if(current < low){
       low = current;}
     else if(current > high){
       high = current;}
   }
  printf("High: %i   Low: %i \n",high,low);
  }

现在我希望能够删除最高和最低，并打印出其他数字。我的问题是，尝试使用哨兵值解决这个问题是明智的吗？制作一个循环的打印语句，如果命中了sentinel值，它只打印什么？

Answer 1

两次处理清单。首先寻找低/高。下次打印，如果不是低/高。

使用\n作为指示输入结束的信号是一个问题，因为\n是scanf("%i"...静默消耗的空白区域。最好用fgets()

检查sscanf()的结果是个好主意。

前两个数字可能不是低/高顺序。

使用"%n"跟踪buffer的进度。

#include <ctype.h>
#include <stdio.h>
#include <stdlib.h>
#include <stdint.h>
#include <limits.h>

int main() {
  int low = INT_MAX;
  int high = INT_MIN;
  int current;
  char buffer[1000];

  fgets(buffer, sizeof buffer, stdin);
  char *p = buffer;
  int n;
  while (sscanf(p, "%i%n", &current, &n) == 1) {
    if (current < low) {
      low = current;
    }
    if (current > high) {
      high = current;
    }
    p += n;
  }
  p = buffer;
  while (sscanf(p, "%i%n", &current, &n) == 1) {
    if ((current != low) && (current != high)) {
      printf("Other: %i\n", current);
    }
    p += n;
  }
printf("High: %i   Low: %i\n", high, low);
return 0;
}

Answer 2

试试这个，

#include<stdio.h>
   main(){
    int low;
    int high;
    int current;
    char c;
    scanf("%i", &low);
    scanf("%i", &high);

    int val;
     do {

      printf("Enter a number:");
     scanf("%d", &current);

     if(current < low){

       val=low;
       low=current;
       current=val;
       }
     else if(current > high){

       val=high;
       high=current;
       current=val;
       }

       printf("%i\n",current); //prints the value if it is in between

   }while((c=getch())!='\n');

  printf("High: %i   Low: %i \n",high,low);//can remove if it this is not required
}

具有Sentinels的C I / O扫描和打印

2 个答案: