我想根据'距离'对多维数组进行排序。价值。如果距离相等,那么我必须比较“创造”的价值。 date然后是价格,最后是字母顺序。我可以根据不同的键值对数组进行排序。
$ array = array(0 => array(' title' =>' title1',' distance' => 200,&#39 ; date' =>' 2014-16',' price' => 12),1 =>数组('标题' => ' title2','距离' => 100,' date' =>' 014-03-15','价' = GT; 17));
数组看起来像这样。优先考虑的是日期等等
答案 0 :(得分:1)
我为这个问题写了一个函数,
结帐我的要点:
https://gist.github.com/chazmead/8829079
<?php
/**
* Sort a 2 dimension array with values in the second dimension
*
* Developer: chazmead89@gmail.com // @RaggaMuffin-4201
*
* Order can be string of a field, which will default to asc
* OR as array(field1,field2...fieldn) each defaulting to asc
* OR as assoc array(field1 => dir[asc|desc], field2 => dir[asc|desc]...fieldn
* => dir[asc|desc])
*
* PHP Sort constants can be used: SORT_ASC | SORT_DESC
*
* @param array $array array to sort - passed by reference
* @param mixed $order
* @return null
*/
function multisort(&$array,$order) {
usort($array, function($a,$b) use ($order) {
$sortMap = array('asc'=>SORT_ASC,'desc'=>SORT_DESC);
$aObj = (object)$a;
$bObj = (object)$b;
if (is_string($order))
$order = array($order);
if (is_object($order))
$order = (array)$order;
$i = 0;
$cOrder = count($order);
foreach($order as $field => $dir) {
if (is_numeric($field)) {
$field = $dir;
$dir = SORT_ASC;
}
// Goto next step when a mis-match is found.
if ($aObj->$field != $bObj->$field)
break;
// All fields match return 0
if (++$i === $cOrder)
return 0;
}
if(!is_numeric($dir)) {
$dir = strtolower($dir);
$dir = $sortMap[$dir];
}
$d = ($dir === SORT_DESC) ? -1 : 1;
$c = ($aObj->$field < $bObj->$field) ? -1 : 1;
return $c*$d;
});
}
这可以这样使用:
$array = array( 0 => array('title'=>'title1', 'distance'=>200, 'date'=>'2014-03-16','price'=>12), 1 => array('title'=>'title2', 'distances'=>100, 'date'=>'014-03-15','price'=>17), );
$order = array('distance' => SORT_ASC, 'created' => SORT_ASC, 'title' => SORT_ASC);
multisort($array,$order);