Question

所以这是我的数据库代码

    private SQLiteDatabase db;
private SQLiteStatement insertStatement;



private String DB_Table = "trainingsplan";


private String INSERT = "insert into " + DB_Table
        + "(zweckkuerzel,aktuellertp,zweck)" + "values (?,?,?)";

它表示错误在选择参数中。

private String SEL_ROW = "select zweckkuerzel,aktuellertp,zweck from "
        + DB_Table;

private String CREATE_TABLE = "create table " + DB_Table
        + "(zweckkuerzel String, " 
        + "aktuellertp String NOT NULL, "
        + "zweck String)";

private String CREATE_INDEX = "create index if not exists " + DB_Table
        + "_ind " + "ON " + DB_Table + " (zweckkuerzel)";

在这里，我创建了我的Dao和Tabel

    TrainingsplanDao trainingsDao= new TrainingsplanDao(db);
    trainingsDao.createTable();
    trainingsDao.fillTable();

这是我道的建构者

public TrainingsplanDao(SQLiteDatabase db) {

    this.db = db;
    try {
        insertStatement = db.compileStatement(INSERT);
        Log.d("ANDRO VEGI", "Create INSERT product");
    } catch (SQLException e) {
        Log.d("ANDRO VEGI", "NO Database, NO INSERT  TrainingsplanDao()");
    }
}

Answer 1

它清楚地表明在db中找不到名为trainingsplan的表。请确保它实际上以相同的名称存在。

SQLiteException：编译时没有这样的表：trainingsplan（代码1）：select语句

1 个答案: