Question

嗨，我是新用的＆＃34; sed＆＃34;我需要使用bash脚本在特殊字符和空格之间显示文本。存在＆＃34;类似＆＃34;问题here但对我不起作用，因为我将在bash脚本中使用该变量。我需要帮助＆＃34; sed＆＃34;不是＆＃34; perl＆＃34;我本地没有index.html。我也在使用Linux。

这是我的变量：

output="$(wget -q http://software.opensuse.org/package/clementine -O - | sed -ne '/<p id="pkg-desc">/, /[.</p>]$/p')"

echo $ output

<p id="pkg-desc">Clementine is a modern music player and library organiser. Clementine is a port of Amarok 1.4, with some features rewritten to take advantage of Qt4.

还有关于如何在<p id="pkg-desc">某些文字之间显示文字的其他替代选项。</p>？或如何删除变量中的<p id="pkg-desc">？

抱歉，我的英语不好：/

Answer 1

这是gnu awk版本

output=$(wget -q software.opensuse.org/package/clementine -O - | awk -v RS='<p id="pkg-desc">' -F"</p>" 'NR==2{print $1}')
echo "$output"
Clementine is a modern music player and library organiser. Clementine is a
port of Amarok 1.4, with some features rewritten to take advantage of Qt4.

Features:

    * Search and play your local music library
    * Listen to internet radio from Last.fm and SomaFM
    * Edit tags on MP3 and OGG files, organise your music
    * Cross-platform - works on Windows, Mac OS X and Linux
    * Native desktop notifications on Linux (libnotify) and Mac OS X (Growl)

Answer 2

output="$(wget -q software.opensuse.org/package/clementine -O - | sed -ne 's|<p id=\"pkg-desc\">\(.*\)</p>$|\1|p')"

"

escpae output="
使用|作为sed分隔符而不是/，因为字符串中存在此char以查找（更易于管理）
使用s///而不是因内部内容（仅限）打印//,//的地址

如何在网站中用sed省略带空格的特殊字符？

2 个答案: