Question

我是c＃的新手。我试图使用以下代码从一种形式导航到另一种形式：

private void button2_Click(object sender, EventArgs e)
    {
        SqlConnection con = new SqlConnection("server=xxxx-PC;database=node;uid=sa;pwd=xxxx;");
        con.Open();
        SqlCommand cmd = new SqlCommand("update nodes set filein='" + textBox1.Text + "' where id='" + textBox2.Text + "' ", con);

        cmd.ExecuteNonQuery();
        con.Close();
        this.Hide();

        Form2 form2 = new Form2();
        form2.show();
    }

但它隐藏了一个表单并抛出异常：

方法或操作未实施

Answer 1

尝试此操作以查找错误的确切内容：

private void button2_Click(object sender, EventArgs e)
{
    SqlConnection con = new SqlConnection("server=xxxx-PC;database=node;uid=sa;pwd=xxxx;");
    SqlCommand cmd = new SqlCommand("update nodes set filein='" + textBox1.Text + "' where id='" + textBox2.Text + "' ", con);
    try
    {
        con.Open();
        cmd.ExecuteNonQuery();
        this.Hide();
        Form2 form2 = new Form2();
        //error here
        //form2.show();
        //replace this with
        form2.Show();
    }
    catch (Exception ex)
    {
        throw ex;
    }
    finally
    {
        con.Close();
    }

}

尝试从一种形式导航到另一种形式时出现异常

1 个答案: