Question

有一些表格，我存储有关患者的信息和测试类型（有3种类型的测试，我存储在其他表中的那些）患者暴露了我得到了：

CREATE TABLE IF NOT EXISTS patients ( 
  ID         INTEGER PRIMARY KEY AUTOINCREMENT, 
  Name     VARCHAR(50) NOT NULL, 
  Tel   VARCHAR(35) NOT NULL, 
  Email      VARCHAR(35) NOT NULL
);

CREATE TABLE IF NOT EXISTS tests ( 
  id_test   INTEGER PRIMARY KEY AUTOINCREMENT, 
  id_patient    INTEGER,
  id_type_test  INTEGER, 
  id_graph  INTEGER, 
  id_graph2 INTEGER, 
  date_test VARCHAR(10),
  FOREIGN KEY (id_patient)  REFERENCES patients(id_patient) ON DELETE CASCADE,
  FOREIGN KEY (id_type_test) REFERENCES type_tests(id_type_test) ); 

CREATE TABLE IF NOT EXISTS type_tests  ( 
    id_type_test     INTEGER PRIMARY KEY AUTOINCREMENT, 
    name_test      VARCHAR(6) NOT NULL
); 

INSERT INTO type_tests values (1,'Audi'); 
INSERT INTO type_tests values (2,'Log'); 
INSERT INTO type_tests values (3,'na'); 

INSERT INTO patients values (1,'John','5653346','john@foe.com');
INSERT INTO patients values (2,'Karla','234346','karla@foe.com');
INSERT INTO patients values (3,'Chad','6667653346','chad@foe.com');

INSERT INTO tests values (1,1,1,50,160,'02/02/2010');
INSERT INTO tests values (2,1,3,55,165,'12/05/2010');
INSERT INTO tests values (3,1,3,65,170,'03/12/2010');

我想检索所有患者的所有患者信息以及最近一次订购的研究，如：

ID Name Tel Email Date Test graph graph2

为了解决这个问题，我首先尝试了对一位患者的所有研究，如：

SELECT te.name_test AS Test,
       e.date_test AS Date,
       e.id_graph AS id_graph,
       e.id_graph2 AS id_graph2 
  FROM tests e 
       INNER JOIN type_tests te 
           ON e.id_type_test = te.id_type_test 
 WHERE e.id_patient=1 
ORDER BY 
       e.date_test DESC;

我得到了：

Test    Date         id_graph   id_graph2
na       12/05/2010   55    165
na       03/12/2010   65    170
Audi    02/02/2010    50    160

如何获得所有患者的所有患者信息？

这是sqlfiddle

期望的输出将是

ID Name Tel       Email         Test Date        id_graph id_graph2
1  John 5653346   john@foe.com  na   12/05/2010  55       165
1  John 5653346   john@foe.com  na   03/12/2010  65       170 
1  John 5653346   john@foe.com  Audi 02/02/2010  50       160

如果有更多患者，我想向所有患者展示......

Answer 1

只需加入patients表格：

SELECT p.ID,
       p.Name,
       p.Tel,
       p.Email,
       te.name_test AS Test,
       e.date_test AS Date, 
       e.id_graph AS id_graph,
       e.id_graph2 AS id_graph2 
  FROM tests e 
       INNER JOIN type_tests te 
           ON e.id_type_test = te.id_type_test 
       INNER JOIN patients p
           ON p.ID = e.id_patient
 WHERE e.id_patient=1 
ORDER BY
       e.date_test DESC;

SQL Fiddle

如何浏览表并通过sqlite中的查询获取结果

1 个答案: