Question

我想在一个页面中多次显示相同的广告单元。只有第一个广告位在第一次工作。当我单击刷新按钮时，会出现第二个插槽。我怎样才能使它发挥作用？

这是我的代码：

<!DOCTYPE html>
<html>
    <head>
        <meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
        <title>Google Advertisement</title>
        <script type='text/javascript'>
            var googletag = googletag || {};
            googletag.cmd = googletag.cmd || [];
            (function() {
                var gads = document.createElement('script');
                gads.async = true;
                gads.type = 'text/javascript';
                var useSSL = 'https:' == document.location.protocol;
                gads.src = (useSSL ? 'https:' : 'http:') +
                        '//www.googletagservices.com/tag/js/gpt.js';
                var node = document.getElementsByTagName('script')[0];
                node.parentNode.insertBefore(gads, node);
            })();
        </script>
        <script type='text/javascript'>
            var slots = {};
            googletag.cmd.push(function() {
                slots['sky1'] = googletag.defineSlot('4757460/Home-Above-Fold-300x250', [300, 250], 'ad-sky1').addService(googletag.pubads());
                slots['sky2'] = googletag.defineSlot('4757460/Home-Above-Fold-300x250', [300, 250], 'ad-sky2').addService(googletag.pubads());
                googletag.pubads().enableSingleRequest();
                googletag.enableServices();
            });

            refreshAds = function(refresh_slots) {
                if (typeof(refresh_slots) == "undefined") {
                    googletag.pubads().refresh();
                } else {
                    googletag.pubads().refresh(refresh_slots);
                }
            };

        </script>
    </head>
    <body>
        <div>
            <button onclick="javascript:refreshAds();
                return false;">Refresh All</button>
            <button onclick="javascript:refreshAds([slots['sky1']]);
                return false;">Refresh Sky 1</button>
            <button onclick="javascript:refreshAds([slots['sky2']]);
                return false;">Refresh Sky 2</button>
        </div>
        <div id='ad-sky1' class="ad">
            <script type='text/javascript'>
            googletag.cmd.push(function() {
                googletag.display('ad-sky1');
            });
            </script>
        </div>
        <div id='ad-sky2' class="ad">
            <script type='text/javascript'>
                googletag.cmd.push(function() {
                    googletag.display('ad-sky2');
                });
            </script>
        </div>
    </body>
</html>

要刷新广告，我已关注https://support.google.com/dfp_sb/answer/3058726?hl=en&ref_topic=1651546

Answer 1

通过谷歌adsense TOS一个广告单元每页只能显示一次。

您只需创建3个具有相同参数的广告单元

即可

如何在一个页面中多次显示Google广告单元？

1 个答案: