Question

输入：d=[['Afiles - segments - ASegment - seg', 'Afiles - segments - ASegment - Conf', 'Afiles - segments - ASegment - alaw', 'Afiles - segments - ASegment - trim', 'Afiles - segments - ASegment - sname', 'Afiles - segments - ASegment - recog', 'Afiles - segments - ASegment - Results', 'Afiles - segments - ASegment - Literal', 'Afiles - amp', 'Afiles - errors', 'Afiles - mishit', 'Afiles - matches', 'Afiles - nomatch', 'Afiles - silence', 'Afiles - filename', 'Afiles - matchesAboveThreshold']] mycode-

for i in d:
    for j in i:
        k=j.replace("Afiles - ","",1)
        if((k.find(" - "))>0):
            s=k.replace("segments - ASegment - ","")
            print s
        else:
            k=j.replace("Afiles - ","",1)
            print k

使用上面的代码，我得到了以下字符串，并将这些字符串附加到嵌套列表：

seg
Conf
alaw
trim
sname
recog
Results
Literal
amp
errors
mishit
matches
nomatch
silence
filename
matchesAboveThreshold

我希望我的输出为：

[['seg','Conf','alaw','trim','sname','recog','Results','Literal','amp','errors','mishit','matches','nomatch','silence','filename','matchesAboveThreshold']]

Answer 1

这可以得到你想要的东西：

result = [[item.split('-')[-1].strip() for item in alist] for alist in d]

与：

相同

result = []
for alist in d:
    sub_list = []
    for item in alist:
        sub_list.append(item.split('-')[-1].strip())
    result.append(sub_list)

我们将sub_list附加到result，因为您期望的输出是列表。

查看python的split函数。它将简化您的代码。

您也可以将代码修改为：

result = []
for i in d:
    sub_list = []
    for j in i:
        k=j.replace("Afiles - ","",1)
        if((k.find(" - "))>0):
            ans=k.replace("segments - ASegment - ","")
        else:
            ans=j.replace("Afiles - ","",1)
        sub_list.append(ans)
    result.append(sub_list)

获得相同的输出

Answer 2

您可以尝试使用split(delimiter)功能：

d = [['Afiles - segments - ASegment - seg', 'Afiles - segments - ASegment - Conf', 'Afiles - segments - ASegment - alaw', 'Afiles - segments - ASegment - trim', 'Afiles - segments - ASegment - sname', 'Afiles - segments - ASegment - recog', 'Afiles - segments - ASegment - Results', 'Afiles - segments - ASegment - Literal', 'Afiles - amp', 'Afiles - errors', 'Afiles - mishit', 'Afiles - matches', 'Afiles - nomatch', 'Afiles - silence', 'Afiles - filename', 'Afiles - matchesAboveThreshold']]

result = []

for l in d:
    result.append([]) # include a new list
    for s in l:
        result[-1].append(s.split(" - ")[-1])

print result

<强>输出：

[['seg', 'Conf', 'alaw', 'trim', 'sname', 'recog', 'Results', 'Literal', 'amp', 'errors', 'mishit', 'matches', 'nomatch', 'silence', 'filename', 'matchesAboveThreshold']]

备注：

请记住，符号some_list[-1]用于访问序列的最后一个元素。

这假设您有列表列表，并且还会返回列表列表。

也可以使用 list comprehension ：
编写

result = [[s.split(' - ')[-1] for s in l] for l in d]

python中的嵌套列表

2 个答案: