简单程序 - 菜单只显示一次

时间:2014-03-17 00:03:49

标签: c++ loops switch-statement logic running-total

我试图跟踪购买的杂货总量。

在我的程序中,每次我购买苹果,奶酪或面包时,程序都应该继续显示菜单。

但它一直在问“有多少苹果?”程序已经计算出苹果的总数而不是返回菜单选择另一个项目。

也许它与我使用过的循环类型有关。

我一直试图解决这个问题。任何帮助,将不胜感激。

#include <iostream>
#include <iomanip>
#include <fstream>
using namespace std;

int main()
{
     double BUDGET;
     const double apple= .60;
     const double lb_cheese= 1.60;
     const double loaf_bread = 2.50;

     double total;
     int count;
     char choice;
     double amount_left;

    cout <<"Welcome! What is the budget for your picnic lunch?"<< endl;
    cin>> BUDGET;

    cout<<"Choose one of the following"<<endl;
    cout<<"-------------------------------------"<<endl;
    cout<<"            MENU             \n "<<endl;
    cout<<"A-Apple      B-Cheese        C-Bread"<<endl;
    cout<<" $0.60       $1.50             $2.50       "<<endl;
    cout<<"-------------------------------------"<<endl;
    cin>> choice;



   while ((choice != 'Q') && (total <BUDGET)) //Q is the sentinel value to "quit" the  program
 {


    switch(choice)

  {

    case 'A':
    case 'a':

    cout<<"How many apples?";
    cin>> count;
    total+= (count *apple);
    break;



    case 'B':
    case 'b':

    cout<<"How many pounds of cheese ?";
    cin>> count;

    total+= (count* lb_cheese);
    break;



    case 'C':
    case 'c':
    cout<<"How many loafs of bread?";
    cin>> count;
    total+= (count * loaf_bread);
    break;



    default:
    cout<<"The entry you have entered is not valid, please try again."<<endl;
  }




if( total > BUDGET)
    { cout<<"You have exceeded your budget please check your cart.\n\n";
       break;
       }



cout<<"Your total is: $"<<setprecision((2))<<fixed<<total<<endl;
amount_left= BUDGET-total;
cout<<"You have $"<<setprecision(2)<<fixed<<amount_left<<" left to spend."<<endl;



 }

    return 0;
}

2 个答案:

答案 0 :(得分:1)

显示菜单不在循环中:

display menu
read option
while (option != quit) {
    do some calculations
}

因此菜单只显示一次。您可以将其更改为无限循环

while (true) {
    display menu
    read option

    if (choice == 'Q' || total >= BUDGET)
        break;

    do some calculations
}

同时尽量避免编写超过50行的函数,将一些逻辑放入一些不同的函数中,只需调用此函数,将其分解为更小的部分,它将更容易阅读,也更容易理解。 / p>

答案 1 :(得分:1)

是的,在循环中显示菜单以显示您想要的次数,并且请记住将变量初始化为良好做法。

Double total = 0.00 //初始化。