Question

我有一系列非常长的网址，其中的密钥格式为myurls21,1，myurls21,2等，我使用以下语句将其分解为组件：

import concurrent.futures
import urllib.request
import json


myurls2 = {}
for x in range(1, 15):
    for y in range(1, 87):

        strvar1 = "%s" % (x)
        strvar2 = "%s" % (y)

        with open("C:\\Python33\\NASDAQ Stock Strings\\NASDAQ_Config_File_{}_{}.txt".format(x,y),"r") as f:
            myurls2[x,y] = f.read().replace('\n', '')
            #print("myurls_" + str(strvar1) + "_" + str(strvar2) + "=", myurls2[x,y])
            #print(myurls2[x,y])

URLS = myurls2.values()

# Retrieve a single page and report the url and contents
def load_url(url, timeout):
    conn = urllib.request.urlopen(url, timeout=timeout)
    return conn.readall()


# We can use a with statement to ensure threads are cleaned up promptly
with concurrent.futures.ThreadPoolExecutor(max_workers=50) as executor:
    # Start the load operations and mark each future with its URL
    future_to_url = {executor.submit(load_url, url, 60): url for url in URLS}

    c = 0


    for future in concurrent.futures.as_completed(future_to_url):
        url = future_to_url[future]



        a = ''
        b = ''
        c += 1


        for url in URLS:
            a = url.rsplit("=", 1)[-1]
            print(myurls2.keys())

如何打印拆分到日志中的每个URL的密钥？我已经尝试了print(myurls2.keys())，但它会打印存储在字典中的所有密钥（URLS是根据myurls2字典的内容定义的。）

Answer 1

如果要迭代字典中的键和值，可以这样做：

for key, url in myurls2.items():
    print(key)
    a = url.rsplit("=", 1)[-1]

如果您想要传递给concurrent的网址的密钥，请重构以允许：

future_to_url = {executor.submit(load_url, url, 60): (key, url)
                 for key, url in myurls2.items()}

现在您可以访问它了：

for future in concurrent.futures.as_completed(future_to_url):
    key, url = future_to_url[future]
    # print key and process url

迭代并打印字典的键而不是其值？

1 个答案: