我想通过PHP通过GData API订阅YouTube频道。
我如何在PHP中发帖?
我尝试了这样,但页面一直在加载:
<?php
session_start();
include 'gdata.php' // For $DEVKEY
function post_xml($url, $xml) {
$ch = curl_init();
curl_setopt($ch, CURLOPT_URL, $url);
curl_setopt($ch, CURLOPT_HEADER, true);
curl_setopt($ch, CURLINFO_HEADER_OUT, true);
curl_setopt($ch, CURLOPT_HTTPHEADER, Array(
"Content-Type: application/atom+xml",
"Content-Length: 1024",
"Authorization: Bearer $token",
"GData-Version: 2",
"X-GData-Key: key=$DEVKEY"));
curl_setopt($ch, CURLOPT_POST, 1);
curl_setopt($ch, CURLOPT_POSTFIELDS, array('data' => $xml );
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, 0);
curl_setopt($ch, CURLOPT_SSL_VERIFYHOST, 0);
$result = curl_exec($ch);
$info = curl_getinfo($ch);
curl_close($ch);
return $result;
}
$token = $_SESSION['token'];
$xml = '<?xml version="1.0" encoding="UTF-8"?>
<entry xmlns="http://www.w3.org/2005/Atom"
xmlns:yt="http://gdata.youtube.com/schemas/2007">
<category scheme="http://gdata.youtube.com/schemas/2007/subscriptiontypes.cat"
term="channel"/>
<yt:username>GoogleDevelopers</yt:username>
</entry>';
$url = 'https://gdata.youtube.com/feeds/api/users/default/subscriptions';
echo post_xml($url, $xml);
?>
在HttpRequester中我已经设法做了一个HTTP Post Request并且它有效。我认为问题是请求的内容。如何通过PHP(cURL)正确地给出“内容”中的文本(查看截图)?
谢谢:)
答案 0 :(得分:1)
只需将$xml
作为POSTFIELDS,它就应该有效:
curl_setopt($ch, CURLOPT_POSTFIELDS, $xml);
并添加正确的内容长度:
"Content-Length: ".strlen($xml),
当您计划进行更多操作时,例如PUT请求包含数据和大量REST请求,我建议使用某种类型的包Httpful。 Curl有它的陷阱......
答案 1 :(得分:0)
您可以查看下面的代码,希望它有所帮助
$headers = array(
"Content-type: text/xml",
"Content-length: " . strlen($xml),
"Connection: close",
);
$ch = curl_init($url);
curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, false);
curl_setopt($ch, CURLOPT_POST, 1);
curl_setopt($ch, CURLOPT_POSTFIELDS, $xml);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_HTTPHEADER, $headers);
$res = curl_exec($ch);
curl_close($ch);
return json_decode($res);