Question

我只是学习PHP代码而且我在下面有一个IF语句似乎不起作用。我有其他IF语句，如下面但是有3个或更少的OR语句，它们似乎只能找到。

      if ($AT_Med_1_3 == '' or $AT_Med_1_3 == NULL or $AT_Med_1_3 == ' ' or $AT_Med_1_3 = 'None')
      {`enter code here`
//          Echo 'Doing $AT_ Input';
          ?>
 <select name="AT_Med_1_3">
        <option value="None">None</option>
        <option value="Oral_Zofran">Oral Zofran</option>
        <option value="IV_Zofran">IV_Zofran</option>
        <option value="Oxygen">Oxygen</option>
        <option value="Ibuprofen">Ibuprofen</option>
        <option value="Aetaminothen">Aetaminothen</option>
        <option value="Upinephrne">Upinephrne</option>
        <option value="Xopenex">Xopenex</option>
        <option value="Albuterol">Albuterol</option>
        <option value="Valium">Valium</option>
        <option value="Magnesiunsulphate">Magnesiunsulphate</option>
        <option value="Diphenhyamine">Diphenhyamine</option>
        <option value="Ketorolac">Ketorolac</option>
        <option value="Promethazion">Promethazion</option>
        <option value="Oral_Fluids_Soup">Oral Fluids Soup</option>
        <option value="Oral_Fluids_Electrolyte">Oral Fluids Electrolyte</option>
        <option value="Oral_Fluids_Water">Oral Fluids Water</option>        
      </select> 
          <?php
      }  else {
//          echo 'Showing $AT_';
          echo $AT_Med_1_3;
          echo nl2br("\n");
      }
?>

如果我将IF语句更改为几个If else语句，它可以工作但是代码很难看

      <?php
//      if ($AT_Med_1_1 == '' or $AT_Med_1_1 == NULL or $AT_Med_1_1 == ' ' or $AT_Med_1_1 = 'None')
    if ($AT_Med_1_1 == '')      
{
    goto test1;
} else if ($AT_Med_1_1 == NULL)
{
    goto test1;
} else if ($AT_Med_1_1 == ' ')
{
    goto test1;
} else if ($AT_Med_1_1 == 'None')
{
    goto test1;
}
    goto test;          

//          Echo 'Doing Input';
test1:         
          ?>
      <select name="AT_Med_1_1">
        <option value="None">None</option>
        <option value="Oral_Zofran">Oral Zofran</option>
        <option value="IV_Zofran">IV_Zofran</option>
        <option value="Oxygen">Oxygen</option>
        <option value="Ibuprofen">Ibuprofen</option>
        <option value="Aetaminothen">Aetaminothen</option>
        <option value="Upinephrne">Upinephrne</option>
        <option value="Xopenex">Xopenex</option>
        <option value="Albuterol">Albuterol</option>
        <option value="Valium">Valium</option>
        <option value="Magnesiunsulphate">Magnesiunsulphate</option>
        <option value="Diphenhyamine">Diphenhyamine</option>
        <option value="Ketorolac">Ketorolac</option>
        <option value="Promethazion">Promethazion</option>
        <option value="Oral_Fluids_Soup">Oral Fluids Soup</option>
        <option value="Oral_Fluids_Electrolyte">Oral Fluids Electrolyte</option>
        <option value="Oral_Fluids_Water">Oral Fluids Water</option>        
      </select>
          <?php
          goto endtest;
 //     }  else {
//          echo 'Showing $AT_';

test: 
          echo $AT_Med_1_1;
          echo nl2br("\n");
endtest:          
//      }
?>

我愿意更好地建议如何编写这个IF语句。

Answer 1

我认为您的主要问题是=而非==，但为了简化if，trim()会将任何空格删除到''和{ {1}}检查empty()和''：

PHP＆lt; 5.5.0

null

PHP＆gt; = 5.5.0

$AT_Med_1_1 = trim($AT_Med_1_1); if (empty($AT_Med_1_1) || $AT_Med_1_1 == 'None')

请注意，if (empty(trim($AT_Med_1_1)) || $AT_Med_1_1 == 'None')还会将empty()和false值（0和"0"）视为空。

在您的情况下，大多数情况下，0.0也是正确的OR运算符。

具有四个或更多＆＃34; OR＆＃34;的IF语句在声明中

1 个答案: