Question

我有一个字符串数组[x，y，z]和一个int数组[2,3,4]，我需要通过附加两个来创建一个数组，但最后3个值乘以整数int数组，如下： [X，Y，Z，XX，YYY，ZZZZ]。我无法弄清楚如何做到这一点。我写的是：

public static String[] bigArr (String[] letters, int[] numbers) {
        int l = letters.length;
        int n = numbers.length;
        String[] answer = new String[l+n];
        for (int i=0; i<n;i++){
                answer[i]=letters[i]+numbers[i];

        }
        return answer;      
    }

显然它在这一点上是胡说八道，但我被困住了，需要一个很好的解释如何做到这一点。我是Java的新手。

Answer 1

1。首先，将字母复制到answer

2。然后，对于每个字母l[i]，

answer[l + i - 1] = string_consisting_of_letter_l[i]_repeated_n[i]_times

Answer 2

试试这个：

public static void main(String[] args) throws Exception {
    String[] letters = {"x", "y", "z"};
    int[] numbers = {2, 3, 4};

    String[] result = bigArr(letters, numbers);

    // prints [x, y, z, xx, yyy, zzzz]
    System.out.println(Arrays.toString(result));
}

private static String[] bigArr(String[] letters, int[] numbers) {
    int lettersLength = letters.length;
    int numbersLength = numbers.length;

    String[] result = new String[lettersLength + numbersLength];

    for (int n = 0; n < lettersLength; ++n) {
        result[n] = letters[n];
    }

    StringBuilder sb = new StringBuilder();
    for (int n = lettersLength; n < result.length; ++n) {
        sb.setLength(0); // reset the StringBuilder

        for (int m = 0; m < numbers[n - lettersLength]; ++m) {
            sb.append(letters[n - lettersLength]);
        }

        result[n] = sb.toString();
    }

    return result;
}

通过根据另一个int数组的值重复每个元素来填充字符串数组

2 个答案: