Question

我不知道我在哪里收到错误但我无法通过id删除该行。这是我的代码。我只删除了脚本而不是编辑脚本所以请忽略它。

<?php include "includes/connection.php";?>
<?php include "includes/header.php";?>
<?php
    if(isset($_POST['menu_submit'])){
        $item_name = mysql_real_escape_string($_POST['item_name']);
        $item_link = mysql_real_escape_string($_POST['item_link']);

        $insert_query = "INSERT INTO navbar (navbar_title, navbar_link) values('$item_name', '$item_link')";

        if($item_name=="" || $item_link==""){
            $required = '<div class="error">All Fields are Required</div>';
        }
        else{
            if(mysql_query($insert_query)){
                $added = '<div class="success">Menu Item Added Successfully</div>';
            }
            else{
                $failed = '<div class="error">Failed to Add Menu Item</div>';
            }
        }
    }
?>

            <div id="content">
                <h2>Add Menu Item</h2>
                <?php  if(isset($added)){echo $added;} ?>
                <?php  if(isset($failed)){echo $failed;} ?>
                <?php  if(isset($required)){echo $required;} ?>
                <form method="post" action="add_menu.php">
                    Menu item Name: <input type="text" name="item_name">
                    Menu item Link: <input type="text" name="item_link">
                    <input type="submit" name="menu_submit" value="Add Item Now">
                </form>
                </br>
                <table>
                    <tr>
                        <th>Item Name</th>
                        <th>Item Link</th>
                        <th colspan="2">Options</th>
                    </tr>
                <?php
                    $run_query = "SELECT * From navbar";
                    $get_query = mysql_query($run_query);

                    while($rows=mysql_fetch_array($get_query)){
                        $get_item_id = $rows['navbar_id'];
                        $get_item_name = $rows['navbar_title'];
                        $get_item_link = $rows['navbar_link'];
                ?>
                    <tr>
                        <td><?php echo $get_item_name; ?></td>
                        <td><?php echo $get_item_link; ?></td>
                        <td><a href="add_menu.php?edit=<?php echo $get_item_id; ?>">Edit</a></td>
                        <td><a href="add_menu.php?delete=<?php echo $get_item_id; ?>">Delete</a></td>
                    </tr>
                <?php }?>
                </table>
            </div>
<?php include "includes/footer.php";?>

这是我的删除脚本，请忽略我正在处理的编辑脚本。

<?php
    if(isset($_GET['edit'])){$edit_item_id = $_GET['edit'];}
    if(isset($_GET['delete'])){$delete_item_id = $_GET['delete'];}

    $delete_query = 'DELETE FROM navbar where id="$delete_item_id"';
    if(mysql_query($delete_query)){
        $item_deleted = '<div class="success">Item has been Deleted</div>';
    }
    else{
        $item_not_deleted = '<div class="error">Item did not Deleted Successfully</div>';
    }
?>

Answer 1

如果设置了

，您将检查错误的变量

更改此

if(isset($edit_item_id)){$edit_item_id = $_GET['edit'];}
if(isset($delete_item_id)){$delete_item_id = $_GET['delete'];}

到此

if(isset($_GET['edit'])) $edit_item_id = $_GET['edit'];
if(isset($_GET['delete'])) $delete_item_id = $_GET['delete'];

此外，您很容易受到SQL注入攻击请确保验证，清理变量并开始使用MySQLi

Answer 2

查询错误：

$delete_query = 'DELETE FROM navbar where id="$delete_item_id"';

改为使用：

$delete_query = "DELETE FROM navbar WHERE id='$delete_item_id'";

编辑：

改变这两行：

if(isset($_GET['edit'])){$edit_item_id = $_GET['edit'];}
if(isset($_GET['delete'])){$delete_item_id = $_GET['delete'];}

Answer 3

我不确定您为什么要检查$ delete_item_id，我认为您打算检查并查看是否已使用$ _GET传递了值。

其次，您需要确保创建的字符串允许变量。我个人更喜欢将它们连接起来。

<?php
    if(!isset($_GET['delete'])){$delete_item_id = $_GET['delete'];}

    $delete_query = "DELETE FROM navbar where id=" . $delete_item_id ."";
    if(mysql_query($delete_query)){
        $item_deleted = '<div class="success">Item has been Deleted</div>';
    }
    else{
        $item_not_deleted = '<div class="error">Item did not Deleted Successfully</div>';
    }
?>

Answer 4

怎么样？

$delete_query = "DELETE FROM navbar WHERE id='{$delete_item_id}'";

也：

if(!isset($delete_item_id)){$delete_item_id = $_GET['delete'];}

在这里注意一点变化......

我无法通过id从mysql中删除数据

4 个答案: