Question

我正在使用Google搜索中的联系表单。我似乎无法弄清楚如何通过Ajax将下拉列表（select）中的值发送到联系表单的php文件。

请查看我的jsfiddle。 http://jsfiddle.net/CBSeZ/

<?php
if($_POST)
{
    //check if its an ajax request, exit if not
    if(!isset($_SERVER['HTTP_X_REQUESTED_WITH']) AND strtolower($_SERVER['HTTP_X_REQUESTED_WITH']) != 'xmlhttprequest') {
        die();
    } 

    $to_Email       = "email@email.com"; 
    $subject        = 'TimeKeeperPro Email'; 

    //check $_POST vars are set, exit if any missing
    if(!isset($_POST["userName"]) || !isset($_POST["userEmail"]) || !isset($_POST["userSubject"]) || !isset($_POST["userMessage"]))
    {
        die();
    }

    //Sanitize input data using PHP filter_var().
    $user_Name        = filter_var($_POST["userName"], FILTER_SANITIZE_STRING);
    $user_Email       = filter_var($_POST["userEmail"], FILTER_SANITIZE_EMAIL);
    $user_Subject     = filter_var($_POST["userSubject"], FILTER_SANITIZE_STRING);
    $user_Message     = filter_var($_POST["userMessage"], FILTER_SANITIZE_STRING);

    //additional php validation
    if(strlen($user_Name)<1) // If length is less than 4 it will throw an HTTP error.
    {
        header('HTTP/1.1 500 Your name is too short or empty!');
        exit();
    }
    if(!filter_var($user_Email, FILTER_VALIDATE_EMAIL)) //email validation
    {
        header('HTTP/1.1 500 Please enter a valid email!');
        exit();
    }

    if(strlen($user_Message)<5) //check emtpy message
    {
        header('HTTP/1.1 500 Your message is too short! Please enter something.');
        exit();
    }

    //proceed with PHP email.
     $headers = 'From: '.$user_Email.'' . "\r\n" .
    'Reply-To: '.$user_Email.'' . "\r\n" .
    'MIME-Version: 1.0' . "\r\n" .
    'Content-type: text/html; charset=iso-8859-1' . "\r\n" .
    'X-Mailer: PHP/' . phpversion();

    @$sentMail = mail($to_Email, $subject, $user_Message .'  -'.$user_Name,$userSubject, $headers);

    if(!$sentMail)
    {
        header('HTTP/1.1 500 Something went wrong.. Sorry!');
        exit();
    }else{
        echo 'Dear '.$user_Name .', thank you for your email! ';
        echo 'It has arrived to our inbox. We will get back to you within 2 business days.';
    }
}
?>

Answer 1

请说清楚，你需要做任何工作......然后使用jQuery ajax帖子。

$( "#subject" ).change(function() {
//url
//here set post to your php page
//response
});

Answer 2

我面前没有确切的错误，但是PHP可能会在你的错误日志中吐出这样的错误：

Unknown constant userSubject, assuming $userSubject

$userSubject当然是null 原因是$_POST变量中的未引用键 - $_POST[userSubject]。

将其更改为$_POST["userSubject"]，它应该开始工作。

Answer 3

最有可能只是错字，你的小提琴不起作用，因为第45行还有额外的括号（见控制台输出）。并且您的PHP脚本缺少引号：

$user_Subject     = filter_var($_POST[userSubject], FILTER_SANITIZE_STRING);

更改为

$user_Subject     = filter_var($_POST["userSubject"], FILTER_SANITIZE_STRING);

通过Ajax发送下拉数据

3 个答案: