Question

我正在编写一个Android应用程序，它具有受权限保护的广播接收器。接收来自经认证的应用程序的请求的广播接收器扫描硬编码IP地址的端口80。它返回套接字连接尝试的结果。在我的代码中，我有从OnReceive ( )方法调用的套接字连接。我可以到达接收器，因为我可以看到吐司消息。但是，Exception E捕获了套接字连接。这是接收器的代码：

 package com.example.naveenbreceive;

import java.io.IOException;
import java.net.InetSocketAddress;
import java.net.Socket;
import java.net.UnknownHostException;

import android.os.Bundle;
import android.app.Activity;
import android.content.ActivityNotFoundException;
import android.content.BroadcastReceiver;
import android.content.Context;
import android.content.Intent;
import android.content.IntentFilter;
import android.util.Log;
import android.view.Menu;
import android.widget.Toast;

public class breceiver extends Activity {

    BroadcastReceiver mReceiver = new BroadcastReceiver() {
        @Override
          public void onReceive(Context context, Intent intent) {
            String Target="107.20.112.24";
            int i=80;
            int timeout=1000;
            Toast.makeText(getApplicationContext(),"Intent Received",Toast.LENGTH_LONG).show();
            Log.i("INFO","toast launched");    

            try {
                Socket socket = new Socket();
                socket.connect(new InetSocketAddress(Target, i), timeout);
                if (socket.isConnected())
                {Toast.makeText(getApplicationContext(), "Connected to port 80", Toast.LENGTH_LONG).show();
                 socket.close();
                }
                else
                {Toast.makeText(getApplicationContext(), "Unable to Connect port 80", Toast.LENGTH_LONG).show();
                 socket.close();
                }

            } 
            catch (UnknownHostException e) {
                // TODO Auto-generated catch block
                Toast.makeText(getApplicationContext(),"UnknownHost Exception",Toast.LENGTH_LONG).show();
                e.printStackTrace();
            }

            catch (IOException e) {
                // TODO Auto-generated catch block
                Toast.makeText(getApplicationContext(),"IO Exception",Toast.LENGTH_LONG).show();
                e.printStackTrace();
            }

            catch (Exception e) {
                // TODO Auto-generated catch block
                Toast.makeText(getApplicationContext(),"Exception",Toast.LENGTH_LONG).show();
                e.printStackTrace();
            }




        }       
        };


    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        // TODO Auto-generated method stub
        IntentFilter filterView = new IntentFilter();
        filterView.addAction("com.example.HACKING");
        registerReceiver(mReceiver, filterView,"com.example.permission.naveen", null);
        Toast.makeText(getApplicationContext(),"Inside Receiver",Toast.LENGTH_LONG).show();


    }

Answer 1

广播接收器位于UI线程上。您无法在UI线程上进行联网。您需要在Thread或AsyncTask中执行此操作。

此外，BroadcastReceivers应该非常快，并且做的工作很少。他们的设计应该是一个快速通知，然后你在其他地方做繁重的工作，所以下一个应用程序可以得到通知。网络IO对接收器来说太过分了。

无法从OnReceive（）连接到远程套接字

1 个答案: