Question

我想替换dot /？ /！然后间隔（如果有的话）到断裂线char \n并消除空格。因此，如果：hello world. It's nice.我希望它为hello world.\nIt'snice.\n 这就是我的想法（但它不起作用，否则我不会写这个问题哈哈？）

re.sub(r'\.!?( *)', r'.\n\1', line)

谢谢！

Answer 1

没有环视：

>>> import re
>>> line="hello world! What? It's nice."
>>> re.sub(r'([.?!]+) *', r'\1\n', line)   # Capture punctuations; discard spaces
"hello world!\nWhat?\nIt's nice.\n"

>>> line="hello world! His thoughts trailed away... What?"
>>> re.sub(r'([.?!]+) *', r'\1\n', line)
'hello world!\nHis thoughts trailed away...\nWhat?\n'

Answer 2

将空格或字符串的结尾与正面后视匹配：

re.sub(r'(?<=[.?!])( +|\Z)', r'\n', text)

因为这只匹配标点符号前面的空格，所以不需要使用反向引用。

+确保此处仅匹配空格后跟空格。文字：

"His thoughts trailed away... His heart wasn't in it!"

否则会收到太多的换行符。

演示：

>>> import re
>>> text = "hello world. It's nice."
>>> re.sub(r'(?<=[.?!])( +|\Z)', r'\n', text)
"hello world.\nIt's nice.\n"
>>> text = "His thoughts trailed away... His heart wasn't in it!"
>>> re.sub(r'(?<=[.?!])( +|$)', r'\n', text)
"His thoughts trailed away...\nHis heart wasn't in it!\n"

Answer 3

你试过replace吗？

print text.replace('. ','.\n').replace('? ','?\n').replace('! ','!\n')

Python正则表达式：替换空格后的点和符号

3 个答案: