我有一个包含13列和5行的简单工作表。当我申请$ sheet-> removeColumn(' F',8);标头被替换为空字符串而不是被删除,并且正文行保持不变。有什么想法吗?
在removeColumn之前转储:
...
[3]=> array(13) {
[0]=> string(8) "Apellido"
[1]=> string(6) "Nombre"
[2]=> string(11) "English Use"
[3]=> string(9) "Listening"
[4]=> string(5) "Nivel"
[5]=> string(5) "Grupo"
[6]=> string(14) "Valor por hora"
[7]=> string(9) "Duración"
[8]=> string(11) "Valor Sence"
[9]=> string(15) "Costo Adicional"
[10]=> string(11) "Valor Total"
[11]=> string(7) "Horario"
[12]=> string(8) "Profesor"
}
[4]=> array(13) {
[0]=> string(10) "Estudiante"
[1]=> string(5) "Nuevo"
[2]=> string(3) "N/A"
[3]=> string(3) "N/A"
[4]=> string(7) "Starter"
[5]=> string(3) "N/A"
[6]=> string(3) "N/A"
[7]=> string(3) "N/A"
[8]=> string(3) "N/A"
[9]=> string(3) "N/A"
[10]=> string(3) "N/A"
[11]=> string(3) "N/A"
[12]=> string(3) "N/A"
}
$sheet->removeColumn('F', 8);
removeColumn后转储:
...
[3]=> array(13) {
[0]=> string(8) "Apellido"
[1]=> string(6) "Nombre"
[2]=> string(11) "English Use"
[3]=> string(9) "Listening"
[4]=> string(5) "Nivel"
[5]=> string(0) ""
[6]=> string(0) ""
[7]=> string(0) ""
[8]=> string(0) ""
[9]=> string(0) ""
[10]=> string(0) ""
[11]=> string(0) ""
[12]=> string(0) ""
}
[4]=> array(13) {
[0]=> string(10) "Estudiante"
[1]=> string(5) "Nuevo"
[2]=> string(3) "N/A"
[3]=> string(3) "N/A"
[4]=> string(7) "Starter"
[5]=> string(3) "N/A"
[6]=> string(3) "N/A"
[7]=> string(3) "N/A"
[8]=> string(3) "N/A"
[9]=> string(3) "N/A"
[10]=> string(3) "N/A"
[11]=> string(3) "N/A"
[12]=> string(3) "N/A"
}