Question

        var serverData = serverConnection.connect("login.php", pairs);

        RootObject json = JsonConvert.DeserializeObject<RootObject>(await serverData);

        foreach (Logined m in json.logined)
        {

        }


        public class Logined
        {

            public string id { get; set; }
            public string firsname { get; set; }
            public string lastname { get; set; }
            public string email { get; set; }
            public string phone { get; set; }
            public string profilePic { get; set; }
            public string thumbnail { get; set; }
        }

        public class RootObject
        {
            public Logined logined { get; set; }
        }

它所说的每个错误都不能对getenumerator的公共定义类型的变量进行操作

Answer 1

您的根对象只包含一个Logined，因此无需枚举。

    public class RootObject
    {
        public Logined logined { get; set; } //not a collection
    }

    foreach (Logined m in json.logined) //json.logined is a single object (not a collection)
    {

    }

如果服务器返回Logined集合，则必须更改RootObject定义。

    public class RootObject
    {
        public Logined[] logined { get; set; } //array of Logined
    }

对每个进行反序列化Json对象

1 个答案: