Question

我有代码进行搜索。但搜索结果不在同一张表中。所有搜索结果都显示在不同的表格中。如何让它们出现在一个表格中？

屏幕截图：

Screenshot of my application

这是我的代码：

> search.php

<?php

    $query = $_GET['query'];


    $min_length = 1;


    if(strlen($query) >= $min_length){ 

        $query = htmlspecialchars($query);

        $query = mysql_real_escape_string($query);

        $raw_results = mysql_query("SELECT * FROM barang WHERE (`tanggal` LIKE '%".$query."%')") or die(mysql_error());


        if(mysql_num_rows($raw_results) > 0){ 

            while($results = mysql_fetch_assoc($raw_results)){
                ?>

                <table width="107%" class="view">
        <thead>
            <tr>
        <th width="180">Tanggal</th>
        <th width="150">Barang Masuk</th>
        <th width="90">Bijih Keluar</th>
        <th width="120">Kantong Hitam Keluar</th>
        <th width="120">Kantong Putih Keluar</th>
        <th width="90">Stok Bijih</th>
        <th width="90">Stok Kantong Hitam</th>
        <th width="90">Stok Kantong Putih</th>
        <th width="130">Catatan</th>
            </tr>
        </thead>



                    <td><?php echo $results['tanggal']; ?></td>



                <td><?php echo $results['barang_in']; ?></td>


                        <td><?php echo $results['bijih_out']; ?></td>


                <td><?php echo $results['htm_out']; ?></td>

                <td><?php echo $results['pth_out']; ?></td>

                <td><?php echo $results['bijih']; ?></td>

                <td><?php echo $results['kantong_htm']; ?></td>

                <td><?php echo $results['kantong_pth']; ?></td>

                <td><?php echo $results['note']; ?></td>
   <?php             
            }

        }
        else{ // if there is no matching rows do following
            echo "Hasil tidak bisa ditemukan atau tidak ada di dalam database.";
        }

    }
    else{ 
        echo "Minimum length is ".$min_length;
    }
?>

那么如何让搜索结果只显示在一个表中呢？我把表格代码错了吗？或者是其他东西？还有一个问题，如何为每个结果添加数字？提前感谢您的时间和帮助。

Answer 1

将<table>标记移到while循环之外。

应该是这样的..

  echo "<table width="107%" class=/"view/">";
  while($results = mysql_fetch_assoc($raw_results)){
                ?>

  <!-- Comment this 
                <table width="107%" class="view">

  -->
  <thead>

Answer 2

将<table>标记移到while循环之外，并在while循环中添加<TR>标记，不要忘记关闭标记。对于序列号，您必须将另一个变量作为计数器引入。在下面给出的代码中，我添加了$i。如果您已在代码中使用$ i，请更改它。我认为更改代码后会看起来像

?>
    <table width="107%" class="view">
      <thead>
        <tr>
          <th>SN</th>//new Line
          <th width="180">Tanggal</th>
          <th width="150">Barang Masuk</th>
          <th width="90">Bijih Keluar</th>
          <th width="120">Kantong Hitam Keluar</th>
          <th width="120">Kantong Putih Keluar</th>
          <th width="90">Stok Bijih</th>
          <th width="90">Stok Kantong Hitam</th>
          <th width="90">Stok Kantong Putih</th>
          <th width="130">Catatan</th>
        </tr>
      </thead>
<?php
    $i=1;//new line
    while($results = mysql_fetch_assoc($raw_results)){
?>
    <tr>
      <td><?php echo $i; ?> </td>//new line
      <td><?php echo $results['tanggal']; ?></td>
      <td><?php echo $results['barang_in']; ?></td>
      <td><?php echo $results['bijih_out']; ?></td>
      <td><?php echo $results['htm_out']; ?></td>
      <td><?php echo $results['pth_out']; ?></td>
      <td><?php echo $results['bijih']; ?></td>
      <td><?php echo $results['kantong_htm']; ?></td>
      <td><?php echo $results['kantong_pth']; ?></td>
      <td><?php echo $results['note']; ?></td>
    </tr>
<?php             
    $i++;//new line
    }
?>
</table>
<?php
}
else{ // if there is no matching rows do following
  echo "Hasil tidak bisa ditemukan atau tidak ada di dalam database.";
}

Answer 3

使用此

<?php
    $query = $_GET['query'];
    $min_length = 1;
    if(strlen($query) >= $min_length)
    { 
        $query = htmlspecialchars($query);
        $query = mysql_real_escape_string($query);
        $raw_results = mysql_query("SELECT * FROM barang WHERE (`tanggal` LIKE '%".$query."%')") or die(mysql_error());
        if(mysql_num_rows($raw_results) > 0)
        { 
?>
        <table width="107%" class="view">
        <thead>
            <tr>
                <th width="180">Tanggal</th>
                <th width="150">Barang Masuk</th>
                <th width="90">Bijih Keluar</th>
                <th width="120">Kantong Hitam Keluar</th>
                <th width="120">Kantong Putih Keluar</th>
                <th width="90">Stok Bijih</th>
                <th width="90">Stok Kantong Hitam</th>
                <th width="90">Stok Kantong Putih</th>
                <th width="130">Catatan</th>
            </tr>
        </thead>
<?php
        while($results = mysql_fetch_assoc($raw_results))
        {
            <tr>
                <td><?php echo $results['tanggal']; ?></td>
                <td><?php echo $results['barang_in']; ?></td>
                <td><?php echo $results['bijih_out']; ?></td>
                <td><?php echo $results['htm_out']; ?></td>
                <td><?php echo $results['pth_out']; ?></td>
                <td><?php echo $results['bijih']; ?></td>
                <td><?php echo $results['kantong_htm']; ?></td>
                <td><?php echo $results['kantong_pth']; ?></td>
                <td><?php echo $results['note']; ?></td>
            </tr>
   <?php             
        }
?>
        </table>
<?php

        }
        else
        { // if there is no matching rows do following
            echo "Hasil tidak bisa ditemukan atau tidak ada di dalam database.";
        }

    }
    else
    { 
        echo "Minimum length is ".$min_length;
    }
?>

如何使用PHP和＆amp ;;在一个表中显示搜索结果MySQL的？

3 个答案: