我有一个字符串。
string strToProcess = "fkdfdsfdflkdkfk@dfsdfjk72388389@kdkfkdfkkl@jkdjkfjd@jjjk@";
我需要在字符串中每次出现“@”符号后添加换行符。
我的输出应该是这样的
fkdfdsfdflkdkfk@
dfsdfjk72388389@
kdkfkdfkkl@
jkdjkfjd@
jjjk@
答案 0 :(得分:438)
string text = "fkdfdsfdflkdkfk@dfsdfjk72388389@kdkfkdfkkl@jkdjkfjd@jjjk@";
text = text.Replace("@", "@" + System.Environment.NewLine);
答案 1 :(得分:64)
您可以在@符号后添加换行符号,如下所示:
string newString = oldString.Replace("@", "@\n");
您还可以使用NewLine
类中的Environment
属性(我认为它是环境)。
答案 2 :(得分:18)
之前的答案很接近,但为了满足@
符号保持接近的实际要求,您希望它为str.Replace("@", "@" + System.Environment.NewLine)
。这将保留@
符号并为当前平台添加适当的换行符。
答案 3 :(得分:9)
然后只需修改以前的答案:
Console.Write(strToProcess.Replace("@", "@" + Environment.NewLine));
如果您不想在文本文件中添加换行符,请不要保留它。
答案 4 :(得分:6)
简单的字符串替换将完成这项工作。看看下面的示例程序:
using System;
namespace NewLineThingy
{
class Program
{
static void Main(string[] args)
{
string str = "fkdfdsfdflkdkfk@dfsdfjk72388389@kdkfkdfkkl@jkdjkfjd@jjjk@";
str = str.Replace("@", "@" + Environment.NewLine);
Console.WriteLine(str);
Console.ReadKey();
}
}
}
答案 5 :(得分:6)
正如其他人所说的那样,新行char会在windows中的文本文件中为你提供一个新行。 尝试以下方法:
using System;
using System.IO;
static class Program
{
static void Main()
{
WriteToFile
(
@"C:\test.txt",
"fkdfdsfdflkdkfk@dfsdfjk72388389@kdkfkdfkkl@jkdjkfjd@jjjk@",
"@"
);
/*
output in test.txt in windows =
fkdfdsfdflkdkfk@
dfsdfjk72388389@
kdkfkdfkkl@
jkdjkfjd@
jjjk@
*/
}
public static void WriteToFile(string filename, string text, string newLineDelim)
{
bool equal = Environment.NewLine == "\r\n";
//Environment.NewLine == \r\n = True
Console.WriteLine("Environment.NewLine == \\r\\n = {0}", equal);
//replace newLineDelim with newLineDelim + a new line
//trim to get rid of any new lines chars at the end of the file
string filetext = text.Replace(newLineDelim, newLineDelim + Environment.NewLine).Trim();
using (StreamWriter sw = new StreamWriter(File.OpenWrite(filename)))
{
sw.Write(filetext);
}
}
}
答案 6 :(得分:3)
根据您对其他人的回复,您正在寻找类似的内容。
string file = @"C:\file.txt";
string strToProcess = "fkdfdsfdflkdkfk@dfsdfjk72388389@kdkfkdfkkl@jkdjkfjd@jjjk@";
string[] lines = strToProcess.Split(new char[] { '@' }, StringSplitOptions.RemoveEmptyEntries);
using (StreamWriter writer = new StreamWriter(file))
{
foreach (string line in lines)
{
writer.WriteLine(line + "@");
}
}
答案 7 :(得分:2)
string str = "fkdfdsfdflkdkfk@dfsdfjk72388389@kdkfkdfkkl@jkdjkfjd@jjjk@";
str = str.Replace("@", Environment.NewLine);
richTextBox1.Text = str;
答案 8 :(得分:1)
string strToProcess = "fkdfdsfdflkdkfk@dfsdfjk72388389@kdkfkdfkkl@jkdjkfjd@jjjk@";
var result = strToProcess.Replace("@", "@ \r\n");
Console.WriteLine(result);
答案 9 :(得分:0)
您也可以使用string[] something = text.Split('@')
。确保使用单引号括起“@”以将其存储为char
类型。
这将把字符存储到包括每个“@”在内的各个单词作为单个单词。然后,您可以使用for循环输出每个(element + System.Environment.NewLine
)或使用System.IO.File.WriteAllLines([file path + name and extension], [array name])
将其写入文本文件。如果该位置中不存在指定的文件,则会自动创建该文件。
答案 10 :(得分:0)
protected void Button1_Click(object sender, EventArgs e)
{
string str = "fkdfdsfdflkdkfk@dfsdfjk72388389@kdkfkdfkkl@jkdjkfjd@jjjk@";
str = str.Replace("@", "@" + "<br/>");
Response.Write(str);
}
答案 11 :(得分:0)
using System;
using System.IO;
using System.Text;
class Test
{
public static void Main()
{
string strToProcess = "fkdfdsfdflkdkfk@dfsdfjk72388389@kdkfkdfkkl@jkdjkfjd@jjjk@";
strToProcess.Replace("@", Environment.NewLine);
Console.WriteLine(strToProcess);
}
}