pdo中的参数错误

时间:2014-03-15 09:56:08

标签: php mysql database api

我有一个php文件,它充当程序和我的数据库之间的抽象。我试着让它返回一个值,我收到了这个错误:

ERROR: SQLSTATE[42000]: Syntax error or access violation: 1064 You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ': USERNAME
        ORDER BY id DESC
        LIMIT 1' at line 2

我的API的整个代码是:

<?php
header("Content-Type: application/json; charset=UTF-8");
require 'UHCauth.php';
try {
    $conn = new PDO("mysql:host=$mysql_serv;dbname=$mysql_db", 
$mysql_user, $mysql_pass);
$conn->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
$conn->setAttribute(PDO::ATTR_EMULATE_PREPARES, false);

if(isset($_GET['USERNAME'])) {
    $USERNAME = $_GET['USERNAME'];
    $stmt = $conn->prepare(
        "SELECT * FROM $mysql_table
        WHERE USERNAME = : USERNAME
        ORDER BY id DESC
        LIMIT 1"
    );
    $stmt->execute(array('USERNAME' => $USERNAME));

    $row = $stmt->fetch(PDO::FETCH_ASSOC);

    echo json_encode($row);
} else {
    $stmt = $conn->prepare(
        "SELECT * FROM $mysql_table
        ORDER BY
            McVersion DESC,
            ModVersion DESC
        LIMIT 1"
    );
    $stmt->execute();

    $row = $stmt->fetch(PDO::FETCH_ASSOC);

    echo json_encode($row);
}
} catch(PDOException $e) {
    echo 'ERROR: ' . $e->getMessage();
}
?>

应该使用用户名并以JSON格式返回该用户名的行。这段代码以前用于不同的项目,现在决定不工作。

1 个答案:

答案 0 :(得分:2)

更改此

 WHERE USERNAME = : USERNAME
                   ^--//dont make sapce here

 WHERE USERNAME = :USERNAME